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Magnetic EffectQuestion and Answers: Page 1

Question Number 150783 Answers: 0 Comments: 0

The current in the windings on a toroid is 2A. There are 400turns and the mean circumferential length is 40cm. With the aid of a search coil and charge measuring instrument,the magnetic field is found to be 1.0T. calculate: i)magnetic intensity ii)magnetization iii)the equivalent surface current

$$\mathrm{The}\:\mathrm{current}\:\mathrm{in}\:\mathrm{the}\:\mathrm{windings}\:\mathrm{on}\:\mathrm{a}\:\mathrm{toroid} \\ $$$$\mathrm{is}\:\mathrm{2A}.\:\mathrm{There}\:\mathrm{are}\:\mathrm{400turns}\:\mathrm{and}\:\mathrm{the}\:\mathrm{mean} \\ $$$$\mathrm{circumferential}\:\mathrm{length}\:\mathrm{is}\:\mathrm{40cm}.\:\mathrm{With} \\ $$$$\mathrm{the}\:\mathrm{aid}\:\mathrm{of}\:\mathrm{a}\:\mathrm{search}\:\mathrm{coil}\:\mathrm{and}\:\mathrm{charge} \\ $$$$\mathrm{measuring}\:\mathrm{instrument},\mathrm{the}\:\mathrm{magnetic} \\ $$$$\mathrm{field}\:\mathrm{is}\:\mathrm{found}\:\mathrm{to}\:\mathrm{be}\:\mathrm{1}.\mathrm{0T}.\:\mathrm{calculate}: \\ $$$$\left.\mathrm{i}\left.\right)\mathrm{magnetic}\:\mathrm{intensity}\:\mathrm{ii}\right)\mathrm{magnetization} \\ $$$$\left.\mathrm{iii}\right)\mathrm{the}\:\mathrm{equivalent}\:\mathrm{surface}\:\mathrm{current} \\ $$$$ \\ $$$$ \\ $$

Question Number 147624 Answers: 0 Comments: 0

The current in the windings on a toroid is 2.0A.There are 400 turns and the mean circumferential length is 40cm.With the aid of a search coil and charge measuring instrument the magnetic field is found to be 1.0T.calculate: i)magnetic density ii)magnetization iii) magnetic susceptibility

$$\mathrm{The}\:\mathrm{current}\:\mathrm{in}\:\mathrm{the}\:\mathrm{windings}\:\mathrm{on}\:\mathrm{a}\: \\ $$$$\mathrm{toroid}\:\mathrm{is}\:\mathrm{2}.\mathrm{0A}.\mathrm{There}\:\mathrm{are}\:\mathrm{400}\:\mathrm{turns} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{circumferential}\:\mathrm{length} \\ $$$$\mathrm{is}\:\mathrm{40cm}.\mathrm{With}\:\mathrm{the}\:\mathrm{aid}\:\mathrm{of}\:\mathrm{a}\:\mathrm{search} \\ $$$$\:\mathrm{coil}\:\mathrm{and}\:\mathrm{charge}\:\mathrm{measuring}\:\mathrm{instrument} \\ $$$$\mathrm{the}\:\mathrm{magnetic}\:\mathrm{field}\:\mathrm{is}\:\mathrm{found}\:\mathrm{to}\:\mathrm{be} \\ $$$$\mathrm{1}.\mathrm{0T}.\mathrm{calculate}: \\ $$$$\left.\mathrm{i}\left.\right)\mathrm{magnetic}\:\mathrm{density}\:\mathrm{ii}\right)\mathrm{magnetization} \\ $$$$\left.\mathrm{iii}\right)\:\mathrm{magnetic}\:\mathrm{susceptibility} \\ $$

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Two large parallel metal plates carrying opposite charges are seperated by a distance of 0.2m,and the potential difference between them is 0.5KV. (a)Calculate the magnitude of the uniform electric field between them. (b)Also calculate the workdone by this field on a charge of 4.0×10^(−9) C when it moves from the plate of higher potential to that of lower potential.

$${Two}\:{large}\:{parallel}\:{metal}\:{plates}\:{carrying} \\ $$$${opposite}\:{charges}\:{are}\:{seperated}\:{by}\:{a} \\ $$$${distance}\:{of}\:\mathrm{0}.\mathrm{2}{m},{and}\:{the}\:{potential} \\ $$$${difference}\:{between}\:{them}\:{is}\:\mathrm{0}.\mathrm{5}{KV}. \\ $$$$\left({a}\right){Calculate}\:{the}\:{magnitude}\:{of}\:{the} \\ $$$${uniform}\:{electric}\:{field}\:{between}\:{them}. \\ $$$$\left({b}\right){Also}\:{calculate}\:{the}\:{workdone}\:{by} \\ $$$${this}\:{field}\:{on}\:{a}\:{charge}\:{of}\:\mathrm{4}.\mathrm{0}×\mathrm{10}^{−\mathrm{9}} {C} \\ $$$${when}\:{it}\:{moves}\:{from}\:{the}\:{plate}\:{of} \\ $$$${higher}\:{potential}\:{to}\:{that}\:{of}\:{lower} \\ $$$${potential}. \\ $$

Question Number 40815 Answers: 1 Comments: 0

Calculate the magnetic force,F_b on an electron with velocity,v=20j^ m/s which enters a magnetic field of flux density,B=0.6k^ T

$${Calculate}\:{the}\:{magnetic}\:{force},{F}_{{b}} \:{on} \\ $$$${an}\:{electron}\:{with}\:{velocity},{v}=\mathrm{20}\hat {{j}m}/{s} \\ $$$${which}\:{enters}\:{a}\:{magnetic}\:{field}\:{of} \\ $$$${flux}\:{density},{B}=\mathrm{0}.\mathrm{6}\hat {{k}T} \\ $$

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Two parallel plate conductors 1m from each other carry an electric current of 2A each.Find the magnetic force per metre on each wire.

$${Two}\:{parallel}\:{plate}\:{conductors}\:\mathrm{1}{m} \\ $$$${from}\:{each}\:{other}\:{carry}\:{an}\:{electric} \\ $$$${current}\:{of}\:\mathrm{2}{A}\:{each}.{Find}\:{the}\:{magnetic} \\ $$$${force}\:{per}\:{metre}\:{on}\:{each}\:{wire}. \\ $$

Question Number 40946 Answers: 1 Comments: 0

Each of two long straight wires 4cm apart carry equal electric currents and experience a force of 2×10^(−4) N/m. What is the magnitude of the electric current in each?

$${Each}\:{of}\:{two}\:{long}\:{straight}\:{wires}\:\mathrm{4}{cm} \\ $$$${apart}\:{carry}\:{equal}\:{electric}\:{currents} \\ $$$${and}\:{experience}\:{a}\:{force}\:{of}\:\mathrm{2}×\mathrm{10}^{−\mathrm{4}} {N}/{m}. \\ $$$${What}\:{is}\:{the}\:{magnitude}\:{of}\:{the} \\ $$$${electric}\:{current}\:{in}\:{each}? \\ $$

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