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MensurationQuestion and Answers: Page 13

Question Number 105883 Answers: 3 Comments: 0

Question Number 105404 Answers: 1 Comments: 0

Cube ABCD.EFGH with length side 2 cm. Point P is the center of ABFE plane. The distance of HP line and the BG line is __

$${Cube}\:{ABCD}.{EFGH}\:{with} \\ $$$${length}\:{side}\:\mathrm{2}\:{cm}.\:{Point}\:{P}\:{is}\:{the} \\ $$$${center}\:{of}\:{ABFE}\:{plane}.\:{The} \\ $$$${distance}\:{of}\:{HP}\:{line}\:{and}\:{the}\:{BG} \\ $$$${line}\:{is}\:\_\_\: \\ $$

Question Number 105356 Answers: 1 Comments: 0

Given a cube ABCD.EFGH. if α is the angle BEH & BEG , find the value of cos α ?

$$\mathcal{G}{iven}\:{a}\:{cube}\:{ABCD}.{EFGH}. \\ $$$${if}\:\alpha\:{is}\:{the}\:{angle}\:{BEH}\:\&\:{BEG}\:, \\ $$$${find}\:{the}\:{value}\:{of}\:\mathrm{cos}\:\alpha\:? \\ $$

Question Number 104877 Answers: 1 Comments: 0

find x

$$ \\ $$$${find}\:{x} \\ $$

Question Number 104841 Answers: 3 Comments: 3

Question Number 104280 Answers: 1 Comments: 5

What is the GCD of (1/2), (3/4), ((16)/(30)) ?

$$\boldsymbol{\mathrm{What}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{GCD}}\:\boldsymbol{\mathrm{of}}\: \\ $$$$\frac{\mathrm{1}}{\mathrm{2}},\:\frac{\mathrm{3}}{\mathrm{4}},\:\frac{\mathrm{16}}{\mathrm{30}}\:? \\ $$

Question Number 103945 Answers: 2 Comments: 0

a cube ABCD.EFGH with length side 4 cm. Given point P is midpoint EF. find the distance of line AP to line HB.

$${a}\:{cube}\:{ABCD}.{EFGH}\:{with}\:{length}\:{side} \\ $$$$\mathrm{4}\:{cm}.\:{Given}\:{point}\:{P}\:{is}\:{midpoint}\:{EF}. \\ $$$${find}\:{the}\:{distance}\:{of}\:{line}\:{AP}\:{to}\:{line} \\ $$$${HB}.\: \\ $$

Question Number 103872 Answers: 0 Comments: 3

Question Number 103672 Answers: 1 Comments: 3

Question Number 103652 Answers: 0 Comments: 1

Question Number 103171 Answers: 1 Comments: 1

Question Number 103147 Answers: 2 Comments: 0

Question Number 103001 Answers: 2 Comments: 0

Question Number 102980 Answers: 1 Comments: 6

Question Number 102910 Answers: 1 Comments: 0

(1)Σ_(m = 1) ^n tan^2 (((mπ)/(2n+1))) (2) Π_(m = 1) ^n tan^2 (((mπ)/(2n+1)))

$$\left(\mathrm{1}\right)\underset{\mathrm{m}\:=\:\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\mathrm{tan}\:^{\mathrm{2}} \left(\frac{\mathrm{m}\pi}{\mathrm{2n}+\mathrm{1}}\right) \\ $$$$\left(\mathrm{2}\right)\:\underset{\mathrm{m}\:=\:\mathrm{1}} {\overset{\mathrm{n}} {\prod}}\mathrm{tan}\:^{\mathrm{2}} \left(\frac{\mathrm{m}\pi}{\mathrm{2n}+\mathrm{1}}\right)\: \\ $$

Question Number 101686 Answers: 0 Comments: 5

Question Number 101851 Answers: 1 Comments: 0

Question Number 101110 Answers: 1 Comments: 0

Question Number 100528 Answers: 1 Comments: 2

Question Number 100387 Answers: 1 Comments: 0

Question Number 100162 Answers: 1 Comments: 1

Question Number 99793 Answers: 0 Comments: 4

lim_(n→∞) (1(2(3(4(5(6(....(n.)^(1/2) ..)^(1/2) )^(1/2) )^(1/2) )^(1/2) )^(1/2) )^(1/2) =?

$$\:\:\boldsymbol{{li}}\underset{\boldsymbol{{n}}\rightarrow\infty} {\boldsymbol{{m}}}\:\left(\mathrm{1}\left(\mathrm{2}\left(\mathrm{3}\left(\mathrm{4}\left(\mathrm{5}\left(\mathrm{6}\left(....\left(\mathrm{n}.\right)^{\frac{\mathrm{1}}{\mathrm{2}}} ..\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} =?\:\:\:\right. \\ $$

Question Number 99677 Answers: 0 Comments: 0

Question Number 99133 Answers: 0 Comments: 0

Equilibrate it using oxydation′s number (NH_4 )_2 Cr_2 O_7 →N_2 +H_2 O+Cr_(2 ) O_7

$${Equilibrate}\:{it}\:{using}\:{oxydation}'{s} \\ $$$${number} \\ $$$$\left({NH}_{\mathrm{4}} \right)_{\mathrm{2}} {Cr}_{\mathrm{2}} {O}_{\mathrm{7}} \rightarrow{N}_{\mathrm{2}} +{H}_{\mathrm{2}} {O}+{Cr}_{\mathrm{2}\:\:} {O}_{\mathrm{7}} \\ $$

Question Number 98919 Answers: 0 Comments: 1

Question Number 98607 Answers: 1 Comments: 0

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