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Question Number 187701 by Mingma last updated on 20/Feb/23

Answered by HeferH last updated on 20/Feb/23

let “h” be the height of the top triangle and “a”  the base   ((7ah)/2) = 28   ah = ((28∙2)/7) = 8    Total area = 4a∙4h∙(1/2) = 8ah = 64u^2

$${let}\:``{h}''\:{be}\:{the}\:{height}\:{of}\:{the}\:{top}\:{triangle}\:{and}\:``{a}'' \\ $$$${the}\:{base} \\ $$$$\:\frac{\mathrm{7}{ah}}{\mathrm{2}}\:=\:\mathrm{28} \\ $$$$\:{ah}\:=\:\frac{\mathrm{28}\centerdot\mathrm{2}}{\mathrm{7}}\:=\:\mathrm{8}\: \\ $$$$\:{Total}\:{area}\:=\:\mathrm{4}{a}\centerdot\mathrm{4}{h}\centerdot\frac{\mathrm{1}}{\mathrm{2}}\:=\:\mathrm{8}{ah}\:=\:\mathrm{64}{u}^{\mathrm{2}} \\ $$

Commented by Mingma last updated on 20/Feb/23

Good

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