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Question Number 189614 by Rupesh123 last updated on 19/Mar/23

Answered by Frix last updated on 19/Mar/23

a=2m−1∧1≤m≤14∧b=2n−1∧m+1≤n≤15  a=2m∧1≤m≤14∧b=2n∧m+1≤n≤15  2Σ_(k=1) ^(14) k=210

$${a}=\mathrm{2}{m}−\mathrm{1}\wedge\mathrm{1}\leqslant{m}\leqslant\mathrm{14}\wedge{b}=\mathrm{2}{n}−\mathrm{1}\wedge{m}+\mathrm{1}\leqslant{n}\leqslant\mathrm{15} \\ $$$${a}=\mathrm{2}{m}\wedge\mathrm{1}\leqslant{m}\leqslant\mathrm{14}\wedge{b}=\mathrm{2}{n}\wedge{m}+\mathrm{1}\leqslant{n}\leqslant\mathrm{15} \\ $$$$\mathrm{2}\underset{{k}=\mathrm{1}} {\overset{\mathrm{14}} {\sum}}{k}=\mathrm{210} \\ $$

Commented by Rupesh123 last updated on 19/Mar/23

Excellent!

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