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Question Number 193554 by Mingma last updated on 16/Jun/23
Answered by aba last updated on 17/Jun/23
$$\mathrm{a}=\mathrm{1}\:\wedge\:\mathrm{b}=\mathrm{0}\: \\ $$
Answered by aba last updated on 17/Jun/23
$$\begin{pmatrix}{\mathrm{1}\:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\mathrm{1}}\end{pmatrix}^{\mathrm{k}} =\begin{pmatrix}{\mathrm{1}^{\mathrm{k}} \:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\:\mathrm{1}^{\mathrm{k}} }\end{pmatrix}\:=\begin{pmatrix}{\mathrm{1}\:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\mathrm{1}}\end{pmatrix} \\ $$$$\begin{pmatrix}{\:\:\:\:\mathrm{a}\:\:\:\:\:\:\:\:\:\mathrm{b}}\\{−\mathrm{b}\:\:\:\:\:\:\:\:\mathrm{1}}\end{pmatrix}^{\mathrm{6}} =\:\begin{pmatrix}{\mathrm{1}\:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\mathrm{1}}\end{pmatrix}^{\mathrm{6}} \Rightarrow\:\begin{pmatrix}{\:\:\:\:\mathrm{a}\:\:\:\:\:\:\mathrm{b}}\\{−\mathrm{b}\:\:\:\:\:\:\mathrm{1}}\end{pmatrix}\:=\begin{pmatrix}{\mathrm{1}\:\:\:\:\mathrm{0}}\\{\mathrm{0}\:\:\:\:\mathrm{1}}\end{pmatrix} \\ $$$$\Rightarrow\begin{cases}{\mathrm{a}=\mathrm{1}\:\checkmark}\\{\mathrm{b}=\mathrm{0}\:\checkmark}\end{cases} \\ $$
Commented by Rupesh123 last updated on 17/Jun/23
Perfect ��