Question Number 205639 by mr W last updated on 26/Mar/24
Answered by mahdipoor last updated on 26/Mar/24
![Trapezium−2 Right triangle=area ⇒ [(((r)+(4+r))/2)×4]−[(((4+r)(r))/2)+(((4−r)(r))/2)]=8](Q205650.png)
$${Trapezium}−\mathrm{2}\:{Right}\:{triangle}={area}\:\Rightarrow \\ $$$$\left[\frac{\left({r}\right)+\left(\mathrm{4}+{r}\right)}{\mathrm{2}}×\mathrm{4}\right]−\left[\frac{\left(\mathrm{4}+{r}\right)\left({r}\right)}{\mathrm{2}}+\frac{\left(\mathrm{4}−{r}\right)\left({r}\right)}{\mathrm{2}}\right]=\mathrm{8} \\ $$
Commented by mr W last updated on 26/Mar/24
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Answered by mr W last updated on 26/Mar/24
Commented by mr W last updated on 26/Mar/24
$${CD}//{AB} \\ $$$$\Delta_{{ABC}} =\Delta_{{ABD}} =\frac{\mathrm{4}×\mathrm{4}}{\mathrm{2}}=\mathrm{8}\:\checkmark \\ $$