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Question Number 196023 by pticantor last updated on 16/Aug/23

find the domain of definition of this  function for t∈]0;1[       𝛒(x)=∫_x ^(2x) (1/(lnt))dt             ptiCantor

$${find}\:{the}\:{domain}\:{of}\:{definition}\:{of}\:{this} \\ $$$$\left.{function}\:{for}\:{t}\in\right]\mathrm{0};\mathrm{1}\left[\right. \\ $$$$\:\:\:\:\:\boldsymbol{\rho}\left({x}\right)=\int_{{x}} ^{\mathrm{2}{x}} \frac{\mathrm{1}}{{lnt}}{dt} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{ptiCantor} \\ $$

Answered by sniper237 last updated on 16/Aug/23

t→(1/(lnt))  is continue on   ]0;1[ , and ]1;+∞[  p(x) exist  if   2x , x are in the same interval    ⇒  0< x<1/2   or   1< x

$$\left.{t}\rightarrow\frac{\mathrm{1}}{{lnt}}\:\:{is}\:{continue}\:{on}\:\:\:\right]\mathrm{0};\mathrm{1}\left[\:,\:{and}\:\right]\mathrm{1};+\infty\left[\right. \\ $$$${p}\left({x}\right)\:{exist}\:\:{if}\:\:\:\mathrm{2}{x}\:,\:{x}\:{are}\:{in}\:{the}\:{same}\:{interval} \\ $$$$\:\:\Rightarrow\:\:\mathrm{0}<\:{x}<\mathrm{1}/\mathrm{2}\:\:\:{or}\:\:\:\mathrm{1}<\:{x}\: \\ $$$$\: \\ $$

Commented by York12 last updated on 16/Aug/23

bro please look at the above problem

$${bro}\:{please}\:{look}\:{at}\:{the}\:{above}\:{problem} \\ $$

Commented by York12 last updated on 16/Aug/23

196206

$$\mathrm{196206} \\ $$

Commented by York12 last updated on 16/Aug/23

sorry I meant 196204

$${sorry}\:{I}\:{meant}\:\mathrm{196204} \\ $$

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