Question Number 8969 by lsaBELA last updated on 08/Nov/16
$${ls} \\ $$
Commented by 123456 last updated on 08/Nov/16
![R^3 m={} 1≤i≤a;m[i]={} 1≤i≤a,1≤j≤b;m[i][j]={} 1≤i≤a,1≤j≤b,1≤k≤c;m[i][j][k]=f(i,j,k)](https://www.tinkutara.com/question/Q8970.png)
$$\mathrm{R}^{\mathrm{3}} \\ $$$${m}=\left\{\right\} \\ $$$$\mathrm{1}\leqslant{i}\leqslant{a};{m}\left[{i}\right]=\left\{\right\} \\ $$$$\mathrm{1}\leqslant{i}\leqslant{a},\mathrm{1}\leqslant{j}\leqslant{b};{m}\left[{i}\right]\left[{j}\right]=\left\{\right\} \\ $$$$\mathrm{1}\leqslant{i}\leqslant{a},\mathrm{1}\leqslant{j}\leqslant{b},\mathrm{1}\leqslant{k}\leqslant{c};{m}\left[{i}\right]\left[{j}\right]\left[{k}\right]={f}\left({i},{j},{k}\right) \\ $$