Question Number 203878 by Spillover last updated on 31/Jan/24 $$\mathrm{A}\:\mathrm{compound}\:\mathrm{M}\:\mathrm{is}\:\mathrm{composed}\:\mathrm{of}\:\mathrm{52}.\mathrm{2\%}\: \\ $$$$\mathrm{carbon}\:,\mathrm{13\%}\:\mathrm{hydrogenand}\:\mathrm{the}\:\mathrm{rest}\: \\ $$$$\mathrm{is}\:\mathrm{oxygen}.\mathrm{if}\:\mathrm{the}\:\mathrm{molecuar}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{M}\:\mathrm{is}\:\mathrm{138} \\ $$$$\left(\mathrm{a}\right)\mathrm{The}\:\mathrm{empirical}\:\mathrm{formular} \\ $$$$\left(\mathrm{b}\right)\mathrm{The}\:\mathrm{molecular}\:\mathrm{formular} \\ $$$$\mathrm{31}/\mathrm{1}/\mathrm{2024} \\ $$ Answered by Calculusboy…
Question Number 203879 by Spillover last updated on 31/Jan/24 $$\mathrm{Complete}\:\mathrm{and}\:\mathrm{balance}\:\mathrm{the}\:\mathrm{following}\:\mathrm{chemical}\:\mathrm{reaction}\: \\ $$$$\mathrm{equation} \\ $$$$\left(\mathrm{a}\right)\mathrm{Ca}\:+\:\mathrm{H}_{\mathrm{2}} \mathrm{O}\:\:\rightarrow\:\: \\ $$$$\left(\mathrm{b}\right)\mathrm{BaC}{l}\:+\:\mathrm{H}_{\mathrm{2}} \mathrm{SO}_{\mathrm{4}} \:\:\rightarrow \\ $$$$\left(\mathrm{c}\right)\mathrm{CuSO}_{\mathrm{4}} .\mathrm{5H}_{\mathrm{2}} \mathrm{O}\:\:\:\overset{\mathrm{Heat}\:\mathrm{strongly}} {\rightarrow} \\…
Question Number 116238 by Ar Brandon last updated on 02/Oct/20 $$\mathrm{How}\:\mathrm{long}\:\mathrm{does}\:\mathrm{it}\:\mathrm{take}\:\mathrm{for}\:\mathrm{the}\:\mathrm{disintegration}\:\mathrm{of} \\ $$$$\frac{\mathrm{3}}{\mathrm{10}}\:\mathrm{of}\:\mathrm{an}\:\mathrm{atom}\:\mathrm{with}\:\mathrm{radioactive}\:\mathrm{constant}\:\lambda\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 180902 by nadovic last updated on 19/Nov/22 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{root}\:\mathrm{mean}\:\mathrm{square}\: \\ $$$$\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{molecules}\:\mathrm{of}\:\mathrm{a}\:{Helium} \\ $$$$\mathrm{gas}\:\mathrm{kept}\:\mathrm{in}\:\mathrm{a}\:\mathrm{gas}\:\mathrm{cylinder}\:\mathrm{at}\:\mathrm{400K}. \\ $$$$\:\:\:\:\:\:\left[{Take}\:\mathrm{R}\:=\:\mathrm{8}.\mathrm{3}\:{Jmol}^{−\mathrm{1}} {K}^{−\mathrm{1}} \right] \\ $$$${The}\:{answer}\:{provided}\:{is}\:\mathrm{1}.\mathrm{58}\:{kms}^{−\mathrm{1}} \\ $$$$\mathrm{Please}\:\mathrm{I}\:\mathrm{need}\:\mathrm{help}\:\mathrm{with}\:\mathrm{the}\:\mathrm{solution} \\ $$ Answered…
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Question Number 42663 by Rio Michael last updated on 31/Aug/18 $${if}\:\mathrm{1}.\mathrm{225}\:{g}\:{of}\:{KClO}_{\mathrm{3}} \:{are}\:{heated}. \\ $$$${Calculate}\:{the}\:{mass}\:{of}\:{potassium}\:{Chloride}\:{produced}. \\ $$$${Detemine}\:{the}\:{volume}\:{of}\:{oxygen}\:{obtained}\:{at}\:{r}.{t}.{p} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 38478 by Rio Mike last updated on 26/Jun/18 Commented by Rio Mike last updated on 26/Jun/18 $$\mathrm{The}\:\mathrm{colouring}\:\mathrm{in}\:\mathrm{five}\:\mathrm{soft}\:\mathrm{drinks} \\ $$$$\mathrm{produced}\:\mathrm{by}\:\mathrm{a}\:\mathrm{drink}\:\mathrm{industry}\:\mathrm{were} \\ $$$$\mathrm{analysed}\:\mathrm{on}\:\mathrm{a}\:\mathrm{Paper}\:\mathrm{Chromatography}. \\ $$$$\mathrm{the}\:\mathrm{final}\:\mathrm{chromatogram}\:\mathrm{is}\:\mathrm{show}\:\mathrm{above}.…
Question Number 35197 by Tinkutara last updated on 16/May/18 Answered by ajfour last updated on 17/May/18 $$ \\ $$$$\Rightarrow\:{P}\:=\:\frac{\mathrm{3}×\mathrm{320}}{\mathrm{290}}\:{atm}\:=\frac{\mathrm{96}}{\mathrm{29}}{atm} \\ $$$$\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{96}}{\mathrm{30}−\mathrm{1}}=\frac{\mathrm{96}}{\mathrm{30}}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{30}}\right)\: \\ $$$$\:\:\:\:\:\:\:\:\:\:=\mathrm{3}.\mathrm{2}+\frac{\mathrm{3}.\mathrm{2}}{\mathrm{30}}\:=\:\mathrm{3}.\mathrm{31}{atm} \\ $$$$\frac{{n}−\bigtriangleup{n}}{\mathrm{3}}=\frac{{n}}{\mathrm{3}.\mathrm{31}}…
Question Number 92621 by student work last updated on 08/May/20 Commented by Tony Lin last updated on 08/May/20 $$\mathrm{6}.\mathrm{022}×\mathrm{10}^{\mathrm{23}} ×\mathrm{4}×\mathrm{2} \\ $$$$\Rightarrow{C} \\ $$ Terms…
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