Question Number 207381 by efronzo1 last updated on 13/May/24 Answered by mr W last updated on 13/May/24 $$\frac{{BD}\centerdot{CE}}{{AC}\centerdot{DE}} \\ $$$$=\frac{\left({BE}+{DE}\right)\centerdot{CE}}{\left({AE}+{CE}\right)\centerdot{DE}} \\ $$$$=\frac{\left(\frac{{BE}}{{DE}}+\mathrm{1}\right)\centerdot{CE}}{\left(\frac{{AE}}{{CE}}+\mathrm{1}\right)\centerdot{DE}} \\ $$$$=\frac{\frac{{BC}}{{AD}}+\mathrm{1}}{\frac{{BC}}{{AD}}+\mathrm{1}} \\…
Question Number 203428 by cortano12 last updated on 19/Jan/24 $$\:\cancel{\underbrace{\:}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203304 by ashokhan last updated on 15/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 202830 by dimentri last updated on 04/Jan/24 $$\:\cancel{\underbrace{ }} \\ $$ Answered by mr W last updated on 04/Jan/24 $${lcm}\left(\mathrm{3},\mathrm{5},\mathrm{7},\mathrm{9}\right)=\mathrm{5}×\mathrm{7}×\mathrm{9}=\mathrm{315} \\ $$$$\Rightarrow{n}=\mathrm{315}{k}−\mathrm{1} \\…
Question Number 202749 by Skabetix last updated on 02/Jan/24 Commented by Rasheed.Sindhi last updated on 06/Jan/24 $${What}\:{does}\:{the}\:{question}\:{say}? \\ $$$${pl}\:{translate}\:{in}\:{English}. \\ $$ Commented by Rasheed.Sindhi last…
Question Number 198750 by depressiveshrek last updated on 24/Oct/23 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{following}\:\mathrm{is}\:\mathrm{a}\:\mathrm{tautology}: \\ $$$$\left[\left({p}\veebar{q}\right)\wedge\left({p}\Rightarrow{r}\right)\right]\Rightarrow\left({q}\veebar{r}\right) \\ $$ Answered by MathematicalUser2357 last updated on 29/Dec/23 $$\mathrm{Only}\:\mathrm{know}\:\mathrm{until} \\ $$$$=\sim\left[\left({p}\veebar{q}\right)\wedge\left(\sim{p}\vee{r}\right)\right]\vee\left({q}\veebar{r}\right) \\…
Question Number 198528 by Hridiana last updated on 21/Oct/23 $$\mathrm{3}+{x}+{y}+{z} \\ $$$$\underbrace{\sqrt{{e}^{{e}^{{e}^{.^{.^{.} } } } } }} \\ $$$${xyz}\:{in}\:{y} \\ $$$${What}\:{is}\:{it} \\ $$ Commented by…
Question Number 198288 by Safojon last updated on 16/Oct/23 Answered by mr W last updated on 17/Oct/23 $$\mathrm{4}+{a}={a}\:\mathrm{cosh}\:\frac{{b}}{\mathrm{2}{a}} \\ $$$$\mathrm{11}={a}\:\mathrm{sinh}\:\frac{{b}}{\mathrm{2}{a}} \\ $$$$\left(\mathrm{4}+{a}\right)^{\mathrm{2}} −\mathrm{11}^{\mathrm{2}} ={a}^{\mathrm{2}} \\…
Question Number 197451 by mohaa last updated on 17/Sep/23 $$\:\:\:\:\:\:\mathrm{45557} \\ $$$$+\:\:\mathrm{24456} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196986 by Erico last updated on 05/Sep/23 $$\mathrm{Prove}\:\mathrm{that}\: \\ $$$$\underset{\mathrm{n}\rightarrow+\infty} {\mathrm{lim}n}\underset{\:\mathrm{0}} {\int}^{\:\mathrm{1}} \mathrm{e}^{−\mathrm{nt}\left(\mathrm{1}−\mathrm{ln}\left(\mathrm{1}−\mathrm{t}\right)\right)} \mathrm{dt}=\sqrt{\mathrm{2}\pi} \\ $$ Answered by witcher3 last updated on 07/Sep/23…