Category: Trigonometry

Question Number 212607 by RojaTaniya last updated on 18/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 212557 by tri26112004 last updated on 17/Oct/24 Answered by Ghisom last updated on 17/Oct/24 $$\mathrm{cos}\:{x}\:={c} \\ $$$$\mathrm{sin}\:{x}\:=\sqrt{\mathrm{1}−{c}^{\mathrm{2}} } \\ $$$$\left(\sqrt{\mathrm{1}−{c}^{\mathrm{2}} }\right)^{\mathrm{8}} +{c}^{\mathrm{8}} =…

Question Number 212477 by Durganand last updated on 14/Oct/24 Answered by mehdee7396 last updated on 14/Oct/24 $$\frac{{sin}\mathrm{2}{acosa}−{sinacos}\mathrm{2}{a}}{{sin}\mathrm{2}{asina}} \\ $$$$=\frac{{sina}}{{sin}\mathrm{2}{asina}}=\frac{\mathrm{1}}{{sin}\mathrm{2}{a}}\:\:\checkmark \\ $$ Answered by A5T last…

Question Number 212457 by 281981 last updated on 14/Oct/24 Answered by som(math1967) last updated on 14/Oct/24 $$\:\begin{vmatrix}{{a}}&{{b}}&{{c}}\\{{b}}&{{c}}&{{a}}\\{{c}}&{{a}}&{{b}}\end{vmatrix}=\mathrm{0} \\ $$$$\Rightarrow{a}\left({bc}−{a}^{\mathrm{2}} \right)−{b}\left({b}^{\mathrm{2}} −{ca}\right)+{c}\left({ab}−{c}^{\mathrm{2}} \right)=\mathrm{0} \\ $$$$\Rightarrow{a}^{\mathrm{3}} +{b}^{\mathrm{3}}…

Question Number 212384 by a.lgnaoui last updated on 14/Oct/24 $$\mathrm{Reponse}\:\mathrm{a}\:\mathrm{la}\:\mathrm{question}\:\mathrm{N}° \\ $$$$\mathrm{Q212291}\:\:\:\:\:\:\mathrm{S}\left(\mathrm{ABCD}\right)=\:\:\mathrm{66},\mathrm{69} \\ $$ Commented by hardmath last updated on 12/Oct/24 $$\mathrm{dear}\:\mathrm{professor},\:\mathrm{answer}:\:\mathrm{90} \\ $$ Terms…