Question Number 216592 by Davidtim last updated on 11/Feb/25 $${if}\:{we}\:{have}\:{the}\:{following}\:{system}: \\ $$$$\frac{{tanx}}{{tany}}={a} \\ $$$${x}\pm{y}=\alpha \\ $$$${we}\:{have}\:{the}\:{general}\:{candition}: \\ $$$$−\mathrm{1}\leqslant\left(\frac{{a}−\mathrm{1}}{{a}+\mathrm{1}}\right){sin}\alpha\leqslant\mathrm{1} \\ $$$${if}\:{you}\:{apply}\:{the}\:{general}\:{candition}\:{by} \\ $$$${the}\:{following}\:{system}\:{it}\:{does}\:{not}\:{give} \\ $$$${us}\:{the}\:{reality},\:{despite}\:{this}\:{system}\:{have} \\…
Question Number 216507 by sachipra last updated on 09/Feb/25 Commented by MathematicalUser2357 last updated on 10/Feb/25 Distance formula with no explanation Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 216454 by a.lgnaoui last updated on 08/Feb/25 $$\mathrm{Reponse}\:\mathrm{a}\:\:\mathrm{l}\:\mathrm{exercice}\:\:\mathrm{N8}: \\ $$$$\mathrm{Reponses}\:\mathrm{par}\:\mathrm{ordre}:\left(\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6}\right) \\ $$$$\boldsymbol{\mathrm{imsge}}\:\mathrm{1}\: \\ $$$$\boldsymbol{\mathrm{imsge}}\:\mathrm{2} \\ $$$$\boldsymbol{\mathrm{image}}\:\mathrm{3} \\ $$$$\boldsymbol{\mathrm{imsge}}\:\mathrm{5} \\ $$$$\boldsymbol{\mathrm{imsge}}\:\mathrm{4} \\ $$$$\boldsymbol{\mathrm{imsge}}\:\mathrm{6} \\…
Question Number 216421 by MATHEMATICSAM last updated on 07/Feb/25 $$\mathrm{If}\:{a}\mathrm{sin}\theta\:+\:{b}\mathrm{cos}\theta\:=\:{a}\mathrm{cosec}\theta\:+\:{b}\mathrm{sec}\theta\:\mathrm{then} \\ $$$$\mathrm{prove}\:\mathrm{that}\:\mathrm{each}\:\mathrm{term}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$$$\left({a}^{\frac{\mathrm{2}}{\mathrm{3}}} \:−\:{b}^{\frac{\mathrm{2}}{\mathrm{3}}} \right)\sqrt{{a}^{\frac{\mathrm{2}}{\mathrm{3}}} \:+\:{b}^{\frac{\mathrm{2}}{\mathrm{3}}} }. \\ $$ Answered by mr W last…
Question Number 216202 by mahdipoor last updated on 29/Jan/25 $${prove}\::\: \\ $$$${sin}\left({a}+{b}\right)={sin}\left({a}\right){cos}\left({b}\right)+{sin}\left({b}\right){cos}\left({a}\right) \\ $$ Answered by dionigi last updated on 30/Jan/25 $${e}^{{i}\:\left({a}+{b}\right)\:} =\:\mathrm{cos}\left({a}+{b}\right)\:+\:{i}\:\mathrm{sin}\left({a}+{b}\right) \\ $$$${e}^{{i}\:\left({a}+{b}\right)\:}…
Question Number 216123 by a.lgnaoui last updated on 28/Jan/25 $$\mathrm{determiner}\:\mathrm{la}\:\mathrm{surface}\:\mathrm{de} \\ $$$$\:\left[\mathrm{ADCMNFEB}\right]\:\: \\ $$ Commented by a.lgnaoui last updated on 28/Jan/25 Terms of Service Privacy…
Question Number 216094 by Mingma last updated on 27/Jan/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 216033 by efronzo1 last updated on 26/Jan/25 Answered by mr W last updated on 26/Jan/25 Commented by mr W last updated on 26/Jan/25…
Question Number 215885 by a.lgnaoui last updated on 20/Jan/25 $$\:\mathrm{Area}\:\:\mathrm{of}\:\mathrm{ABC}\:? \\ $$ Commented by a.lgnaoui last updated on 20/Jan/25 Answered by A5T last updated on…
Question Number 215696 by BaliramKumar last updated on 15/Jan/25 Answered by MATHEMATICSAM last updated on 15/Jan/25 $$\mathrm{sec}^{\mathrm{4}} \mathrm{x}\:−\:\mathrm{cosec}^{\mathrm{4}} \mathrm{x}\:−\:\mathrm{2sec}^{\mathrm{2}} \mathrm{x}\:+\:\mathrm{2cosec}^{\mathrm{2}} \mathrm{x}\:=\:\frac{\mathrm{63}}{\mathrm{8}} \\ $$$$\Rightarrow\:\mathrm{sec}^{\mathrm{2}} {x}\left(\mathrm{sec}^{\mathrm{2}} {x}\:−\:\mathrm{2}\right)\:+\:\mathrm{cosec}^{\mathrm{2}}…