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Category: Trigonometry

Question-204729

Question Number 204729 by Amidip last updated on 26/Feb/24 Answered by A5T last updated on 26/Feb/24 $$\frac{{sin}\left(\mathrm{2}{x}\right)}{{AD}}=\frac{{sin}\left(\mathrm{140}−\mathrm{2}{x}\right)}{{AB}};\frac{{sin}\left(\mathrm{140}−\mathrm{3}{x}\right)}{{AD}}=\frac{{sin}\left({x}\right)}{{DC}={AB}} \\ $$$$\Rightarrow\frac{{sin}\left(\mathrm{140}−\mathrm{3}{x}\right)}{{sin}\left({x}\right)}=\frac{{sin}\left(\mathrm{2}{x}\right)}{{sin}\left(\mathrm{140}−\mathrm{2}{x}\right)}\Rightarrow{x}=\mathrm{35}° \\ $$ Terms of Service Privacy…

Prove-the-following-trig-identity-2sin-sin3-sin5-cos-2cos2-cos3-2cos2-tan-2-

Question Number 204293 by depressiveshrek last updated on 11/Feb/24 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{following}\:\mathrm{trig}\:\mathrm{identity}: \\ $$$$\frac{\mathrm{2sin}\alpha+\mathrm{sin3}\alpha+\mathrm{sin5}\alpha}{\mathrm{cos}\alpha−\mathrm{2cos2}\alpha+\mathrm{cos3}\alpha}=\frac{\mathrm{2cos2}\alpha}{\mathrm{tan}\frac{\alpha}{\mathrm{2}}} \\ $$ Commented by Frix last updated on 11/Feb/24 $$\mathrm{Try}. \\ $$$$\alpha=\frac{\pi}{\mathrm{6}}\:\Rightarrow\:\mathrm{lhs}=−\mathrm{5}\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)\:\:\:\:\:\mathrm{rhs}=\mathrm{2}+\sqrt{\mathrm{3}} \\…

Find-the-possible-values-for-x-and-y-if-10cosx-12cos-x-y-5-10sinx-12sin-x-y-20-66-

Question Number 204101 by necx122 last updated on 06/Feb/24 $${Find}\:{the}\:{possible}\:{values}\:{for}\:{x}\:{and}\:{y}\:{if} \\ $$$$\mathrm{10}{cosx}\:+\:\mathrm{12}{cos}\left({x}+{y}\right)=\mathrm{5} \\ $$$$\mathrm{10}{sinx}\:+\:\mathrm{12}{sin}\left({x}+{y}\right)=\mathrm{20}.\mathrm{66} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com