Question Number 207065 by manxsol last updated on 05/May/24 $$ \\ $$$$\:\:\:{f}\left({x}\right)=\left[{cos}\mathrm{2}{x}+{cos}\mathrm{3}{x}\right]\left[{cos}\mathrm{4}{x}+{cos}\mathrm{6}{x}\right]\left[\left[{cosx}+{cos}\mathrm{5}{x}\right]\right. \\ $$$${evaluar}\:\:\:{f}\left(\frac{\mathrm{2}\pi}{\mathrm{13}}\right)\:\: \\ $$ Answered by Berbere last updated on 06/May/24 $$\left.\mathrm{4}{cos}\left({x}\right){cos}\left(\mathrm{5}{x}\right){cos}\left(\mathrm{2}{x}\right){cos}\left(\mathrm{3}{x}\right).\left[{cos}\left(\mathrm{2}{x}\right)+{cos}\left(\:\mathrm{3}{x}\right)\right]\right]{a}\mathrm{2}\left(\right. \\…
Question Number 206970 by MATHEMATICSAM last updated on 02/May/24 $$\mathrm{If}\:\mathrm{sin}\theta\:=\:\frac{{m}^{\mathrm{2}} \:+\:\mathrm{2}{mn}}{{m}^{\mathrm{2}} \:+\:\mathrm{2}{mn}\:+\:\mathrm{2}{n}^{\mathrm{2}} }\:\mathrm{then}\:\mathrm{prove} \\ $$$$\mathrm{that}\:\mathrm{tan}\theta\:=\:\frac{{m}^{\mathrm{2}} \:+\:\mathrm{2}{mn}}{\mathrm{2}{mn}\:+\:\mathrm{2}{n}^{\mathrm{2}} }\:. \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 206971 by MATHEMATICSAM last updated on 02/May/24 $$\mathrm{Construct}\:\mathrm{an}\:\mathrm{angle}\:\mathrm{whose}\:\mathrm{sine}\:\mathrm{is} \\ $$$$\frac{\mathrm{3}}{\mathrm{2}\:+\:\sqrt{\mathrm{5}}}\:. \\ $$ Answered by Rasheed.Sindhi last updated on 02/May/24 $$\mathrm{sin}\theta=\:\frac{\mathrm{3}}{\mathrm{2}\:+\:\sqrt{\mathrm{5}}} \\ $$$$\bullet\theta\:{is}\:{an}\:{angle}\:{of}\:{a}\:{right}\:{triangle} \\…
Question Number 206899 by MATHEMATICSAM last updated on 29/Apr/24 $$\mathrm{If}\:\mathrm{tan}\theta\:=\:\frac{\mathrm{2}{x}\left({x}\:+\:\mathrm{1}\right)}{\mathrm{2}{x}\:+\:\mathrm{1}}\:\mathrm{then}\:\mathrm{find}\:\mathrm{sin}\theta\:\mathrm{and} \\ $$$$\mathrm{cos}\theta. \\ $$ Answered by mathzup last updated on 29/Apr/24 $$\mathrm{1}+{tan}^{\mathrm{2}} \theta\:=\frac{\mathrm{1}}{{cos}^{\mathrm{2}} \theta}\:\Rightarrow{cos}^{\mathrm{2}} \theta\:=\frac{\mathrm{1}}{\mathrm{1}+{tan}^{\mathrm{2}}…
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Question Number 206833 by BaliramKumar last updated on 27/Apr/24 Answered by MATHEMATICSAM last updated on 27/Apr/24 $$\mathrm{If}\:\mathrm{0}\:\leq\:\theta\:\leq\:\frac{\pi}{\mathrm{4}}\:\mathrm{then}\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\leq\:\mathrm{cos}\theta\:\leq\:\mathrm{1}\: \\ $$$$\mathrm{Or},\:\frac{\mathrm{1}}{\mathrm{2}}\:\leq\:\mathrm{cos}^{\mathrm{2}} \theta\:\leq\:\mathrm{1} \\ $$$${x}\mathrm{cos}\theta\:=\:{x}^{\mathrm{2}} \:+\:{p} \\ $$$$\Rightarrow\:{x}^{\mathrm{2}}…
Question Number 206787 by Amidip last updated on 25/Apr/24 Commented by mr W last updated on 25/Apr/24 $${you}\:{don}'{t}\:{tell}\:{what}\:{you}\:{want}\:{to}\:{know}? \\ $$ Terms of Service Privacy Policy…
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Question Number 206618 by MATHEMATICSAM last updated on 20/Apr/24 $$\mathrm{If}\:\mathrm{A}\:=\:\mathrm{sin}^{\mathrm{4}} \theta\:+\:\mathrm{cos}^{\mathrm{4}} \theta\:\mathrm{then}\:\mathrm{select}\:\mathrm{the}\: \\ $$$$\mathrm{correct}\:\mathrm{option}: \\ $$$$\left.\mathrm{i}\right)\:\mathrm{0}\:<\:\mathrm{A}\:<\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\left.\mathrm{ii}\right)\:\mathrm{1}\:<\:\mathrm{A}\:<\:\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$\left.\mathrm{iii}\right)\:\frac{\mathrm{1}}{\mathrm{2}}\:\leq\:\mathrm{A}\:\leq\:\mathrm{1} \\ $$$$\left.\mathrm{iv}\right)\:\frac{\mathrm{3}}{\mathrm{2}}\:\leq\:\mathrm{A}\:\leq\:\mathrm{2} \\ $$ Answered…