Question Number 209892 by lmcp1203 last updated on 25/Jul/24 $${find}\:\:\mathrm{40}^{\mathrm{71}} {mod}\:\mathrm{437}.\:\:\:{thanks} \\ $$$${its}\:\mathrm{67}\:{but}\:{how}? \\ $$ Answered by Rasheed.Sindhi last updated on 25/Jul/24 $$\mathrm{40}^{\mathrm{25}} \equiv\mathrm{14}\:\left({mod}\:\mathrm{437}\right) \\…
Question Number 209860 by lmcp1203 last updated on 23/Jul/24 $$ \\ $$$$\mathrm{Magnitude}\:\mathrm{A}\:\mathrm{varies}\:\mathrm{proportionally}\:\mathrm{with}\:\left(\mathrm{B}\:\mathrm{squared}\:+\:\mathrm{4}\right)\:\mathrm{and}\:\mathrm{magnitude}\:\mathrm{B}\:\mathrm{varies}\:\mathrm{proportionally}\:\mathrm{with} \\ $$$$\left({t}\mathrm{he}\:\mathrm{root}\:\mathrm{of}\:\mathrm{C}\right)\:−\:\mathrm{5}.\:\mathrm{Also}\:\mathrm{when}\:\mathrm{A}\:\mathrm{is}\:\mathrm{16}\:,\:\mathrm{B}\:\mathrm{is}\:\mathrm{12}\:\mathrm{and}\:\mathrm{C}\:\mathrm{takes}\:\mathrm{the}\:\mathrm{value}\:\mathrm{81}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{value}\:\mathrm{that}\:\mathrm{A}\:\mathrm{takes} \\ $$$$\mathrm{wh}{e}\mathrm{n}\:\mathrm{C}\:\mathrm{is}\:\mathrm{49}.\:\:\:{help}\:\:{me}.\:{please}.\:{thanks} \\ $$ Answered by mr W last updated on…
Question Number 209744 by peter frank last updated on 20/Jul/24 Answered by mr W last updated on 20/Jul/24 $${X}={Y}=\frac{\mathrm{180}−\mathrm{40}}{\mathrm{2}}=\mathrm{70}° \\ $$ Answered by Spillover last…
Question Number 209598 by peter frank last updated on 16/Jul/24 Answered by Frix last updated on 16/Jul/24 $${a}:{b}=\mathrm{3}:\mathrm{5} \\ $$$${b}:{c}=\mathrm{2}:\mathrm{4}=\mathrm{5}:\mathrm{10} \\ $$$${a}:{b}:{c}=\mathrm{3}:\mathrm{5}:\mathrm{10} \\ $$ Answered…
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Question Number 209602 by peter frank last updated on 16/Jul/24 Answered by som(math1967) last updated on 16/Jul/24 $$\:{let}\:{number}={x} \\ $$$$\:\frac{\mathrm{120}{x}}{\mathrm{100}}\:−\frac{\mathrm{85}{x}}{\mathrm{100}}=\mathrm{14} \\ $$$$\:\frac{\mathrm{35}{x}}{\mathrm{100}}=\mathrm{14} \\ $$$$\Rightarrow{x}=\frac{\mathrm{14}×\mathrm{100}}{\mathrm{35}}=\mathrm{40} \\…
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Question Number 209453 by peter frank last updated on 10/Jul/24 Commented by peter frank last updated on 10/Jul/24 $$\mathrm{help}\:\mathrm{B} \\ $$ Answered by mr W…
Question Number 209452 by peter frank last updated on 10/Jul/24 Answered by Ghisom last updated on 10/Jul/24 $$\mathrm{12}\:\mathrm{units} \\ $$$$−\mathrm{4}\:\mathrm{units}\:\left(\mathrm{12}/\mathrm{3}\right)\:\mathrm{for}\:\mathrm{sugar}\:=\:\mathrm{8}\:\mathrm{units} \\ $$$$−\mathrm{2}\:\mathrm{units}\:\left(\mathrm{8}/\mathrm{4}\right)\:\mathrm{for}\:\mathrm{soap}\:=\:\mathrm{6}\:\mathrm{units} \\ $$$$\mathrm{6}\:\mathrm{units}\:=\:\mathrm{6000} \\…
Question Number 209342 by essaad last updated on 07/Jul/24 Answered by Berbere last updated on 07/Jul/24 $${U}_{{n}+\mathrm{1}} ={f}\left({U}_{{n}} \right) \\ $$$${x}\overset{{f}} {\rightarrow}\frac{{x}}{\mathrm{2}}+\frac{{x}^{\mathrm{2}} }{\mathrm{4}};{f}\:{increase} \\ $$$${f}\left(\left[\mathrm{0},\mathrm{1}\right]\right)=\left[\mathrm{0},\frac{\mathrm{3}}{\mathrm{4}}\right]\subset\left[\mathrm{0},\mathrm{1}\right]…