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Question-216655

Question Number 216655 by abdelsalam last updated on 14/Feb/25 Answered by issac last updated on 14/Feb/25 $${y}^{\mathrm{4}} ={y}^{\mathrm{2}} −{x}^{\mathrm{2}} \\ $$$${y}^{\mathrm{4}} −{y}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{4}}−\frac{\mathrm{1}}{\mathrm{4}}=−{x}^{\mathrm{2}} \\ $$$$\left({y}^{\mathrm{2}}…

Question-216659

Question Number 216659 by issac last updated on 14/Feb/25 Answered by issac last updated on 14/Feb/25 $$\mathrm{Q216647} \\ $$$$\mathrm{oh}\:\mathrm{Jesus}….\mathrm{shit}…. \\ $$$$\mathrm{and}\:\mathrm{F}_{\mathrm{1}} \left({a},\mathrm{b}_{\mathrm{1}} ,\mathrm{b}_{\mathrm{2}} ,\mathrm{c},{x},{y}\right)\:\mathrm{is} \\…

D-sin-x-2-y-2-tan-x-2-y-2-cos-x-2-y-2-tan-x-2-y-2-dxdy-D-0-pi-4-0-pi-4-

Question Number 216596 by issac last updated on 12/Feb/25 $$\underset{\mathcal{D}} {\int\int}\:\:\:\frac{\mathrm{sin}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)+\mathrm{tan}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)}{\mathrm{cos}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)+\mathrm{tan}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)}\mathrm{d}{x}\mathrm{d}{y} \\ $$$$\mathcal{D}=\left[\mathrm{0},\frac{\pi}{\mathrm{4}}\right]×\left[\mathrm{0},\frac{\pi}{\mathrm{4}}\right] \\ $$ Answered by…

0-1-sin-npix-J-0-j-0m-x-dx-

Question Number 216615 by EmGent last updated on 12/Feb/25 $$\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{sin}\:{n}\pi{x}\:{J}_{\mathrm{0}} \left({j}_{\mathrm{0}{m}} {x}\right){dx} \\ $$ Answered by EmGent last updated on 12/Feb/25 $$\mathrm{Does}\:\mathrm{anyone}\:\mathrm{knows}\:\mathrm{how}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{this}\:? \\…

Question-216572

Question Number 216572 by Samuel12 last updated on 10/Feb/25 Answered by maths2 last updated on 11/Feb/25 $${si}\:\alpha\notin{I}\Rightarrow\alpha=\frac{{a}}{{b}}\in{IQ}\:\:{b} {a}=\mathrm{1}\:{on}\:{va}\:{montrer}\:{Que}\:{b}\mid{a} \\ $$$$\Rightarrow{a}^{{n}} −\underset{{k}=\mathrm{0}} {\overset{{n}−\mathrm{1}} {\sum}}{c}_{{k}} {a}^{{k}} {b}^{{n}−{k}}…

using-first-principle-solve-y-x-2-x-2-is-it-possible-with-first-principle-

Question Number 216537 by klipto last updated on 11/Feb/25 $$\mathrm{using}\:\mathrm{first}\:\mathrm{principle}\:\mathrm{solve} \\ $$$$\mathrm{y}=\frac{\mathrm{x}+\mathrm{2}}{\:\sqrt{\mathrm{x}}+\mathrm{2}} \\ $$$$\mathrm{is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{with}\:\mathrm{first}\:\mathrm{principle} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Res-z-c-f-z-1-2pii-C-f-z-dz-Res-z-1-z-21-z-2-z-1-z-1-3-1-2pii-C-z-21-z-2-z-1-z-1-3-dz-1-2pii-C-z-21-z-2-z-1-z-1-2-z-1-dz-l

Question Number 216493 by issac last updated on 09/Feb/25 $$\mathrm{Res}_{{z}={c}} \left\{{f}\left({z}\right)\right\}=\frac{\mathrm{1}}{\mathrm{2}\pi{i}}\:\oint_{\:\mathrm{C}} \:{f}\left({z}\right)\mathrm{d}{z} \\ $$$$\mathrm{Res}_{{z}=\mathrm{1}} \left\{\frac{{z}^{\mathrm{21}} +{z}^{\mathrm{2}} +{z}+\mathrm{1}}{\left({z}−\mathrm{1}\right)^{\mathrm{3}} }\right\}=\frac{\mathrm{1}}{\mathrm{2}\pi{i}}\:\oint_{\:{C}} \:\frac{{z}^{\mathrm{21}} +{z}^{\mathrm{2}} +{z}+\mathrm{1}}{\left({z}−\mathrm{1}\right)^{\mathrm{3}} }\mathrm{d}{z} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}\pi{i}}\:\oint_{\:{C}} \:\:\frac{\frac{{z}^{\mathrm{21}}…

Prove-or-disprove-that-If-p-k-0-n-3-k-n-gt-0-is-an-integer-then-p-is-prime-

Question Number 216513 by CrispyXYZ last updated on 09/Feb/25 $$\mathrm{Prove}\:\mathrm{or}\:\mathrm{disprove}\:\mathrm{that}: \\ $$$$\mathrm{If}\:{p}=\sqrt{\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\mathrm{3}^{{k}} }\:\left({n}>\mathrm{0}\right)\:\mathrm{is}\:\mathrm{an}\:\mathrm{integer},\:\mathrm{then}\:{p}\:\mathrm{is}\:\mathrm{prime}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com