# Category: None

## Question-204428

Question Number 204428 by sulaymonnorboyev140 last updated on 17/Feb/24 Commented by AST last updated on 17/Feb/24 $${Q}\mathrm{196938} \\$$ Terms of Service Privacy Policy Contact:…

## Question-204405

Question Number 204405 by mathdave last updated on 16/Feb/24 Commented by mathdave last updated on 16/Feb/24 $${pls}\:{someone}\:{should}\:{me}\:{out}\: \\$$ Answered by mr W last updated…

## Question-204389

Question Number 204389 by Ngarmadji last updated on 15/Feb/24 Answered by Frix last updated on 15/Feb/24 $$\frac{\mathrm{2}{x}}{\mathrm{3}}−\frac{\mathrm{2}{x}}{\mathrm{5}}=\mathrm{1}\:\:\frac{{x}}{\mathrm{3}}−\frac{{x}}{\mathrm{5}}=\frac{\mathrm{1}}{\mathrm{2}}\:\:\mathrm{5}{x}−\mathrm{3}{x}=\frac{\mathrm{15}}{\mathrm{2}}\:\:{x}=\frac{\mathrm{15}}{\mathrm{4}} \\$$$$\frac{\mathrm{3}{x}}{\mathrm{5}}−\frac{\mathrm{2}{x}}{\mathrm{15}}+\frac{{x}}{\mathrm{3}}=−\frac{\mathrm{7}}{\mathrm{15}}\:\:\frac{\mathrm{9}{x}−\mathrm{2}{x}+\mathrm{5}{x}}{\mathrm{15}}=−\frac{\mathrm{7}}{\mathrm{15}}\:\:…\:{x}=−\frac{\mathrm{7}}{\mathrm{12}} \\$$ Terms of Service Privacy…

## if-lim-x-a-6-x-1-ax-1-2-find-the-largest-and-smallest-correct-value-for-a-

Question Number 204360 by esmaeil last updated on 14/Feb/24 $${if} \\$$$$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\left[\frac{\left({a}+\mathrm{6}\right){x}+\mathrm{1}}{{ax}+\mathrm{1}}\right]=\mathrm{2}\rightarrow \\$$$${find}\:{the}\:{largest}\:{and}\:{smallest}\:{correct} \\$$$${value}\:{for}\:{a}. \\$$ Answered by AST last updated on…

## Question-204337

Question Number 204337 by SANOGO last updated on 13/Feb/24 Answered by witcher3 last updated on 13/Feb/24 $$\left(\mathrm{3}\right)\Rightarrow\left(\mathrm{2}\right) \\$$$$\mathrm{soitU}\:\mathrm{un}\:\mathrm{ouvert}\:\mathrm{de}\:\mathrm{E}\: \\$$$$\exists\:\mathrm{existe}\:\mathrm{V}\:\mathrm{un}\:\mathrm{ouvert}\:\mathrm{de}\:\mathrm{F} \\$$\mathrm{t}\:\mathrm{elle}\:\mathrm{Que}\:\mathrm{U}=\mathrm{f}^{−} \left(\mathrm{V}\right);\mathrm{car}\:\mathrm{f}\:\mathrm{et}\:\mathrm{bijective}\:\mathrm{donc}\:\mathrm{f}^{−} \\…