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Category: Magnetic Effect

Question-53686

Question Number 53686 by ajfour last updated on 25/Jan/19 Commented by ajfour last updated on 25/Jan/19 $${Charged}\:{particle}\:\left({q},{m}\right)\:{released} \\ $$$${at}\:{origin}.\:{Find}\:{velocity}\:\bar {{v}}\:{as}\:{a} \\ $$$${function}\:{of}\:{the}\:{z}\:{coordinate}. \\ $$$${Electric}\:{field},\:{E}_{\mathrm{0}} \hat…

Question-53342

Question Number 53342 by aseerimad last updated on 20/Jan/19 Commented by tanmay.chaudhury50@gmail.com last updated on 21/Jan/19 $${pls}\:{clarify}\:{direction}\:{of}\: \\ $$$$\overset{\rightarrow} {{E}}={electric}\:{field}\:\:\left({is}\:{it}\:+{ve}\:{x}\:{axis}\:\right) \\ $$$$\overset{\rightarrow} {{V}}={velocity}\:{proton}\left({is}\:{it}\:+{ve}\:{x}\:{axis}\right. \\ $$$$\overset{\rightarrow}…

Question-48310

Question Number 48310 by rahul 19 last updated on 22/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 22/Nov/18 $${current}\:{I}=\frac{{dq}}{{dt}} \\ $$$${E}=\frac{{q}}{{c}}\:\:{so}\:\frac{{dE}}{{dt}}=\frac{{I}}{{c}}\:\:\:{I}={c}\frac{{dE}}{{dt}} \\ $$$${force}\:{on}\:{coducting}\:{slider}\:{F}={IBl} \\ $$$${F}={m}\frac{{dV}}{{dt}}={IBl} \\…

Question-41434

Question Number 41434 by rahul 19 last updated on 07/Aug/18 Commented by rahul 19 last updated on 07/Aug/18 $$\mathrm{If}\:\mathrm{the}\:\mathrm{ammeter}\:\mathrm{A}_{\mathrm{2}\:} \:\mathrm{reads}\:\mathrm{1}.\mathrm{6A}\:\mathrm{and} \\ $$$$\mathrm{ammeter}\:\mathrm{A}_{\mathrm{3}} \:\mathrm{reads}\:\mathrm{0}.\mathrm{4}\:\mathrm{A}\:. \\ $$$$\mathrm{Find}\:\mathrm{reading}\:\mathrm{of}\:\mathrm{ammeter}\:\mathrm{A}_{\mathrm{1}}…

Each-of-two-long-straight-wires-4cm-apart-carry-equal-electric-currents-and-experience-a-force-of-2-10-4-N-m-What-is-the-magnitude-of-the-electric-current-in-each-

Question Number 40946 by Necxx last updated on 29/Jul/18 $${Each}\:{of}\:{two}\:{long}\:{straight}\:{wires}\:\mathrm{4}{cm} \\ $$$${apart}\:{carry}\:{equal}\:{electric}\:{currents} \\ $$$${and}\:{experience}\:{a}\:{force}\:{of}\:\mathrm{2}×\mathrm{10}^{−\mathrm{4}} {N}/{m}. \\ $$$${What}\:{is}\:{the}\:{magnitude}\:{of}\:{the} \\ $$$${electric}\:{current}\:{in}\:{each}? \\ $$ Answered by tanmay.chaudhury50@gmail.com last…

Two-parallel-plate-conductors-1m-from-each-other-carry-an-electric-current-of-2A-each-Find-the-magnetic-force-per-metre-on-each-wire-

Question Number 40945 by Necxx last updated on 29/Jul/18 $${Two}\:{parallel}\:{plate}\:{conductors}\:\mathrm{1}{m} \\ $$$${from}\:{each}\:{other}\:{carry}\:{an}\:{electric} \\ $$$${current}\:{of}\:\mathrm{2}{A}\:{each}.{Find}\:{the}\:{magnetic} \\ $$$${force}\:{per}\:{metre}\:{on}\:{each}\:{wire}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com