Question Number 209853 by peter frank last updated on 23/Jul/24 Commented by mr W last updated on 23/Jul/24 $${the}\:{iron}\:{rod}\:{must}\:{be}\:{of}\:{a}\:{length}\:{of} \\ $$$$\mathrm{44482}\:{cm}! \\ $$ Answered by…
Question Number 209845 by peter frank last updated on 23/Jul/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 209846 by peter frank last updated on 23/Jul/24 Answered by mr W last updated on 23/Jul/24 $${the}\:{result}\:{is}\:{too}\:{large}. \\ $$$$\mathrm{20}×\left(\mathrm{15}−\mathrm{10}\right)×\mathrm{12}×\mathrm{10}^{−\mathrm{6}} =\mathrm{0}.\mathrm{0012}{m} \\ $$$$=\mathrm{1}.\mathrm{2}\:{mm} \\…
Question Number 209840 by peter frank last updated on 23/Jul/24 Answered by mahdipoor last updated on 23/Jul/24 $${M}_{{moon}} ={M}_{{earth}} ={M}={cte} \\ $$$${W}_{{moon}} ={Mg}_{{moon}} \:\:\:\:\:\:\:\:\:\:\:\:{W}_{{earth}} ={Mg}_{{earth}}…
Question Number 209597 by peter frank last updated on 16/Jul/24 Commented by peter frank last updated on 18/Jul/24 $$\mathrm{thank}\:\mathrm{you}\:\mathrm{both} \\ $$ Answered by mr W…
Question Number 209599 by peter frank last updated on 16/Jul/24 Answered by Spillover last updated on 16/Jul/24 Answered by Spillover last updated on 16/Jul/24 Answered…
Question Number 209529 by mr W last updated on 13/Jul/24 Commented by mr W last updated on 13/Jul/24 $${find}\:{u}_{{min}} \:{such}\:{that}\:{the}\:{ball}\:{can}\:{fly} \\ $$$${out}\:{of}\:{the}\:{well}. \\ $$$$\left({collisions}\:{with}\:{the}\:{wall}\:{are}\:{elastic}\right)\: \\…
Question Number 209358 by peter frank last updated on 08/Jul/24 Commented by mr W last updated on 08/Jul/24 $${if}\:{the}\:{bowl}\:{is}\:{smooth},\:{why}\:{should}\:{the}\: \\ $$$${small}\:{block}\:{rotate}\:{with}\:{the}\:{bowl}\:{and} \\ $$$${not}\:{fall}\:{to}\:{the}\:{middle}\:{of}\:{the}\:{bowl}? \\ $$…
Question Number 209359 by peter frank last updated on 08/Jul/24 Commented by mr W last updated on 08/Jul/24 $$“{with}\:{a}\:{vertical}\:{velocity}\:{v}''\:{should}\:{be} \\ $$$$“{with}\:{a}\:{velocity}\:{v}''. \\ $$$${answer}\:\frac{{v}^{\mathrm{2}} −{g}^{\mathrm{2}} {x}^{\mathrm{2}}…
Question Number 209352 by Spillover last updated on 07/Jul/24 Answered by mr W last updated on 08/Jul/24 $${L}={mr}^{\mathrm{2}} \omega={constant} \\ $$$$\omega_{{max}} =\frac{{L}}{{mr}_{{min}} ^{\mathrm{2}} }=\frac{{L}}{{m}\left({a}−{c}\right)^{\mathrm{2}} }…