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Category: Integration

Question-207382

Question Number 207382 by efronzo1 last updated on 13/May/24 Answered by sniper237 last updated on 13/May/24 $$\overset{{X}=^{\mathrm{3}} \sqrt{{x}−\mathrm{2}}} {=}\underset{{X}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{X}^{\mathrm{6}} +\mathrm{2}{X}^{\mathrm{3}} +{X}}{\:^{\mathrm{3}} \sqrt{\mathrm{4}−\mathrm{2}\sqrt{\mathrm{3}{X}^{\mathrm{3}} +\mathrm{4}}−{X}^{\mathrm{3}} \sqrt{\mathrm{3}{X}^{\mathrm{3}}…

Question-207354

Question Number 207354 by NasaSara last updated on 12/May/24 Commented by mr W last updated on 12/May/24 $${there}\:{are}\:{integrals}\:{like}\:{following} \\ $$$$\int\int…\int\int{f}\left({x}_{\mathrm{1}} ,{x}_{\mathrm{2}} ,…,{x}_{{n}} \right){dx}_{\mathrm{1}} {dx}_{\mathrm{2}} …{dx}_{{n}}…

Question-207099

Question Number 207099 by tri26112004 last updated on 06/May/24 Answered by Berbere last updated on 06/May/24 $$=\int_{−\infty} ^{\infty} \frac{{e}^{{i}\pi{ax}} }{\left({x}^{\mathrm{2}} +\beta^{\mathrm{2}} \right)^{{n}+\mathrm{1}} }{dx};{a}\in\mathbb{R}_{+} \\ $$$${if}\:{Imx}\geqslant\mathrm{0}\:\mid{e}^{{i}\pi{ax}}…

0-1-1-x-1-1-x-1-1-x-dx-

Question Number 206962 by Ghisom last updated on 01/May/24 $$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\frac{\sqrt{\mathrm{1}−{x}}}{\:\sqrt{\mathrm{1}−\sqrt{\mathrm{1}−{x}}}+\sqrt{\mathrm{1}+\sqrt{\mathrm{1}−{x}}}}{dx}=? \\ $$ Answered by lepuissantcedricjunior last updated on 02/May/24 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\sqrt{\mathrm{1}−\boldsymbol{{x}}}}{\:\sqrt{\mathrm{1}−\sqrt{\mathrm{1}−\boldsymbol{{x}}}}+\sqrt{\mathrm{1}+\sqrt{\mathrm{1}−\boldsymbol{{x}}}}}\boldsymbol{{dx}}=\boldsymbol{{k}} \\…

can-some-one-find-the-exact-value-of-n-0-1-n-2-

Question Number 206890 by mathzup last updated on 29/Apr/24 $${can}\:{some}\:{one}\:{find}\:{the}\:{exact}\:{value}\:{of} \\ $$$$\sum_{{n}=\mathrm{0}} ^{\infty} \:\frac{\mathrm{1}}{\left({n}!\right)^{\mathrm{2}} } \\ $$ Commented by Frix last updated on 30/Apr/24 $$\mathrm{This}\:\mathrm{is}\:\mathrm{a}\:\mathrm{Modified}\:\mathrm{Bressel}\:\mathrm{Function}\:\mathrm{of}\:\mathrm{the}…