Question Number 71972 by device4438043516@gmail.com last updated on 23/May/20
$$ \\ $$
Commented by MJS last updated on 23/Oct/19
![syntax unknown u=u(x) v=v(x) (d/dx)[u×v]=u′×v+u×v′ or easy to keep in mind: (uv)′=u′v+uv′](https://www.tinkutara.com/question/Q71980.png)
$$\mathrm{syntax}\:\mathrm{unknown} \\ $$$${u}={u}\left({x}\right) \\ $$$${v}={v}\left({x}\right) \\ $$$$\frac{{d}}{{dx}}\left[{u}×{v}\right]={u}'×{v}+{u}×{v}' \\ $$$$\mathrm{or}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{keep}\:\mathrm{in}\:\mathrm{mind}: \\ $$$$\left({uv}\right)'={u}'{v}+{uv}' \\ $$
Commented by benjo last updated on 25/Dec/19
$$\mathrm{what}\:\mathrm{is}\:\mathrm{this}\:\mathrm{sir}? \\ $$