Question Number 102517 by bemath last updated on 09/Jul/20
$$\left(\mathrm{1}+{x}^{\mathrm{2}} \right){dy}\:+\:\left(\mathrm{1}+{y}^{\mathrm{2}} \right){dx}\:=\:\mathrm{0} \\ $$
Commented by bemath last updated on 09/Jul/20
1-x-2-dy-1-y-2-dx-0-