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d-2-y-dx-2-5x-dy-dx-2-6y-ln-x-

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Question Number 82794 by jagoll last updated on 24/Feb/20
(d^2 y/dx^2 ) + 5x ((dy/dx))^2 −6y=ln x
$$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:+\:\mathrm{5}{x}\:\left(\frac{{dy}}{{dx}}\right)^{\mathrm{2}} −\mathrm{6}{y}={ln}\:{x} \\ $$

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