Question Number 55636 by gunawan last updated on 01/Mar/19
![known function f:[−5, 4]→R continues, then E={x ∈ [−5, 4] : f(x)}, then closure from E is...](https://www.tinkutara.com/question/Q55636.png)
$$\mathrm{known}\:\mathrm{function}\:{f}:\left[−\mathrm{5},\:\mathrm{4}\right]\rightarrow\mathbb{R}\:\mathrm{continues}, \\ $$$$\mathrm{then}\:{E}=\left\{{x}\:\in\:\left[−\mathrm{5},\:\mathrm{4}\right]\::\:{f}\left({x}\right)\right\}, \\ $$$$\mathrm{then}\:\mathrm{closure}\:\mathrm{from}\:{E}\:\mathrm{is}… \\ $$