Question Number 155122 by saly last updated on 25/Sep/21
Commented by benhamimed last updated on 25/Sep/21
![/x−3/+3−x≠0 /x−3/= { ((x−3 ;x≥3)),((3−x ;x≤3)) :} /x−3/+3−x= { ((0 ;x≥3)),((6−2x ;x≤0)) :} D=]−∞;3[](https://www.tinkutara.com/question/Q155128.png)
$$/{x}−\mathrm{3}/+\mathrm{3}−{x}\neq\mathrm{0} \\ $$$$/{x}−\mathrm{3}/=\begin{cases}{{x}−\mathrm{3}\:\:\:;{x}\geqslant\mathrm{3}}\\{\mathrm{3}−{x}\:\:\:\:;{x}\leqslant\mathrm{3}}\end{cases} \\ $$$$/{x}−\mathrm{3}/+\mathrm{3}−{x}=\begin{cases}{\mathrm{0}\:\:\:;{x}\geqslant\mathrm{3}}\\{\mathrm{6}−\mathrm{2}{x}\:\:\:;{x}\leqslant\mathrm{0}}\end{cases} \\ $$$$\left.{D}=\right]−\infty;\mathrm{3}\left[\right. \\ $$
Commented by saly last updated on 25/Sep/21
$$\:\:{thank}\:{you} \\ $$