Question Number 91690 by zainal tanjung last updated on 02/May/20
Commented by zainal tanjung last updated on 03/May/20
![Hint=Formula • ((n(n+1))/2) • ((n(n+1)(2n+1))/6) • [((n(n+1))/2)]^2](https://www.tinkutara.com/question/Q91779.png)
$$\mathrm{Hint}=\mathrm{Formula} \\ $$$$\bullet\:\frac{\mathrm{n}\left(\mathrm{n}+\mathrm{1}\right)}{\mathrm{2}} \\ $$$$\bullet\:\:\frac{\mathrm{n}\left(\mathrm{n}+\mathrm{1}\right)\left(\mathrm{2n}+\mathrm{1}\right)}{\mathrm{6}} \\ $$$$\bullet\:\left[\frac{\mathrm{n}\left(\mathrm{n}+\mathrm{1}\right)}{\mathrm{2}}\right]^{\mathrm{2}} \\ $$$$ \\ $$
Answered by malwaan last updated on 02/May/20
$$\mathrm{1}\:\frac{\mathrm{50}×\mathrm{51}}{\mathrm{2}}\:=\:\mathrm{25}×\mathrm{51}=\:\mathrm{1275} \\ $$$$\mathrm{2}\:\frac{\mathrm{113}×\mathrm{114}}{\mathrm{2}}\:=\:\mathrm{113}×\mathrm{57}=\:\mathrm{6441} \\ $$$$\mathrm{3}\:\frac{\mathrm{196}\left(\mathrm{196}+\mathrm{1}\right)\left(\mathrm{2}×\mathrm{196}+\mathrm{1}\right)}{\mathrm{6}} \\ $$$$\:\:\:\:\:\:\:=\:\mathrm{2529086} \\ $$