Question Number 115891 by bemath last updated on 29/Sep/20
$$\mathrm{sec}\:^{\mathrm{2}} \mathrm{10}°+\mathrm{cosec}\:^{\mathrm{2}} \mathrm{20}°+\mathrm{cosec}\:^{\mathrm{2}} \mathrm{40}°−\mathrm{sec}\:^{\mathrm{2}} \mathrm{45}° \\ $$
sec-2-10-cosec-2-20-cosec-2-40-sec-2-45-