Question Number 193210 by otchereabdullai@gmail.com last updated on 07/Jun/23
Answered by MM42 last updated on 07/Jun/23
$$\left({p}+\mathrm{3}{q}\right)^{\mathrm{2}} −\left({p}+\mathrm{3}{q}\right)\left({p}−\mathrm{3}{q}\right)=\left({p}+\mathrm{3}{q}\right)\left({p}+\mathrm{3}{q}−{p}+\mathrm{3}{q}\right)=\mathrm{6}{q}\left({p}+\mathrm{3}{q}\right)\:\checkmark \\ $$
Commented by otchereabdullai@gmail.com last updated on 07/Jun/23
$${nice}!\:{thanks} \\ $$