Question Number 13103 by kashyappushpendrak1811@gmail.c last updated on 14/May/17
$$\:\underset{\:−\mathrm{1}} {\overset{\mathrm{2}} {\int}}\:\frac{\:\mid\:{x}\:\mid\:}{{x}}\:{dx}\:=\: \\ $$
Answered by mrW1 last updated on 14/May/17
![∫_( −1) ^2 (( ∣ x ∣ )/x) dx = ∫_( −1) ^0 (( ∣ x ∣ )/x) dx+∫_( 0) ^2 (( ∣ x ∣ )/x) dx = ∫_( −1) ^0 (−1) dx+∫_( 0) ^2 dx =−1[0−(−1)]+[2−0] =1](https://www.tinkutara.com/question/Q13104.png)
$$\:\underset{\:−\mathrm{1}} {\overset{\mathrm{2}} {\int}}\:\frac{\:\mid\:{x}\:\mid\:}{{x}}\:{dx}\:=\:\underset{\:−\mathrm{1}} {\overset{\mathrm{0}} {\int}}\:\frac{\:\mid\:{x}\:\mid\:}{{x}}\:{dx}+\underset{\:\mathrm{0}} {\overset{\mathrm{2}} {\int}}\:\frac{\:\mid\:{x}\:\mid\:}{{x}}\:{dx} \\ $$$$\:=\:\underset{\:−\mathrm{1}} {\overset{\mathrm{0}} {\int}}\:\left(−\mathrm{1}\right)\:{dx}+\underset{\:\mathrm{0}} {\overset{\mathrm{2}} {\int}}\:\:{dx} \\ $$$$=−\mathrm{1}\left[\mathrm{0}−\left(−\mathrm{1}\right)\right]+\left[\mathrm{2}−\mathrm{0}\right] \\ $$$$=\mathrm{1} \\ $$
Answered by 2002154006 last updated on 14/May/17
