Question Number 198235 by MASANJAJJ last updated on 15/Oct/23
Answered by Rasheed.Sindhi last updated on 15/Oct/23
![y=m∠B [Corresponding angles] x=m∠A [Alternative angles] z=m∠ACB [Same angles] x+y+z=m∠A+m∠B+m∠ACB=180° [Angles of triangle]](https://www.tinkutara.com/question/Q198236.png)
$${y}={m}\angle{B}\:\:\:\:\:\:\:\left[{Corresponding}\:{angles}\right] \\ $$$${x}={m}\angle{A}\:\:\:\:\:\:\left[{Alternative}\:{angles}\right] \\ $$$${z}={m}\angle{ACB}\:\:\:\left[{Same}\:{angles}\right] \\ $$$${x}+{y}+{z}={m}\angle{A}+{m}\angle{B}+{m}\angle{ACB}=\mathrm{180}°\:\left[{Angles}\:{of}\:{triangle}\right] \\ $$$$ \\ $$