Question Number 203613 by mr W last updated on 23/Jan/24
Commented by mr W last updated on 23/Jan/24
$${find}\:\frac{{R}}{{r}}=? \\ $$
Commented by esmaeil last updated on 23/Jan/24
$$\mathrm{4} \\ $$
Answered by mr W last updated on 23/Jan/24
Commented by mr W last updated on 23/Jan/24
$$\left(\mathrm{2}{R}\right)^{\mathrm{2}} −\left({R}+\mathrm{2}{r}\right)^{\mathrm{2}} =\left({R}+{r}\right)^{\mathrm{2}} −{r}^{\mathrm{2}} \\ $$$${R}^{\mathrm{2}} −\mathrm{3}{Rr}−\mathrm{2}{r}^{\mathrm{2}} =\mathrm{0} \\ $$$$\frac{{R}}{{r}}=\frac{\mathrm{3}+\sqrt{\mathrm{17}}}{\mathrm{2}}\approx\mathrm{3}.\mathrm{562} \\ $$