Question Number 211258 by otchereabdullai@gmail.com last updated on 02/Sep/24
Answered by A5T last updated on 02/Sep/24
$$\Rightarrow{tan}\mathrm{2}\theta=\frac{\mathrm{28}}{\mathrm{9}}\Rightarrow\theta=\frac{{tan}^{−\mathrm{1}} \left(\frac{\mathrm{28}}{\mathrm{9}}\right)}{\mathrm{2}}\approx\mathrm{36}.\mathrm{091}° \\ $$