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Question Number 214329 by malwan last updated on 05/Dec/24
what is the coefficient of  x^(50  )  in  (1+2x+3x^2 +...+101x^(100) )(1+x+x^2 +...+x^(25) )
$${what}\:{is}\:{the}\:{coefficient}\:{of} \\ $$$${x}^{\mathrm{50}\:\:} \:{in} \\ $$$$\left(\mathrm{1}+\mathrm{2}{x}+\mathrm{3}{x}^{\mathrm{2}} +…+\mathrm{101}{x}^{\mathrm{100}} \right)\left(\mathrm{1}+{x}+{x}^{\mathrm{2}} +…+{x}^{\mathrm{25}} \right) \\ $$
Answered by mr W last updated on 05/Dec/24
51+50+49+...+26  =(((51+26)×26)/2)=1001 ✓
$$\mathrm{51}+\mathrm{50}+\mathrm{49}+…+\mathrm{26} \\ $$$$=\frac{\left(\mathrm{51}+\mathrm{26}\right)×\mathrm{26}}{\mathrm{2}}=\mathrm{1001}\:\checkmark \\ $$
Commented by malwan last updated on 06/Dec/24
Answered by A5T last updated on 05/Dec/24
=51+50+49+...+26=((51(52))/2)−((25(26))/2)=1001  ...+1001x^(50) +...
$$=\mathrm{51}+\mathrm{50}+\mathrm{49}+…+\mathrm{26}=\frac{\mathrm{51}\left(\mathrm{52}\right)}{\mathrm{2}}−\frac{\mathrm{25}\left(\mathrm{26}\right)}{\mathrm{2}}=\mathrm{1001} \\ $$$$…+\mathrm{1001}{x}^{\mathrm{50}} +… \\ $$
Commented by malwan last updated on 06/Dec/24
thank you sir
$${thank}\:{you}\:{sir} \\ $$

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