Question Number 215718 by mathlove last updated on 16/Jan/25
$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left({ln}\frac{\mathrm{9}}{\mathrm{2}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}{x}} =? \\ $$$$ \\ $$
Answered by mehdee7396 last updated on 17/Jan/25
$${if}\:\:{x}\rightarrow+\infty\Rightarrow{lim}\left({ln}\frac{\mathrm{9}}{\mathrm{2}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}{x}} =+\infty \\ $$$${if}\:\:{x}\rightarrow−\infty\Rightarrow{lim}\left({ln}\frac{\mathrm{9}}{\mathrm{2}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}{x}} =\mathrm{0} \\ $$$$ \\ $$