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Question-215808




Question Number 215808 by efronzo1 last updated on 19/Jan/25
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$$\:\:\:\downharpoonleft\underline{\:} \\ $$
Answered by golsendro last updated on 19/Jan/25
  = e^(lim_(x→0)  (((a^x +b^x +c^x −3)/x)))      = e^(lim_(x→0)  (ln a .a^x + ln b. b^x + ln c. c^x ))      = e^(ln (abc))  = 8
$$\:\:=\:\mathrm{e}^{\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\frac{{a}^{{x}} +{b}^{{x}} +{c}^{{x}} −\mathrm{3}}{{x}}\right)} \\ $$$$\:\:\:=\:{e}^{\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\mathrm{ln}\:{a}\:.{a}^{{x}} +\:\mathrm{ln}\:{b}.\:{b}^{{x}} +\:\mathrm{ln}\:{c}.\:{c}^{{x}} \right)} \\ $$$$\:\:\:=\:{e}^{\mathrm{ln}\:\left({abc}\right)} \:=\:\mathrm{8}\: \\ $$

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