Question Number 215957 by LG last updated on 22/Jan/25
$${b}^{\mathrm{2}} −\mathrm{4}{ac} \\ $$
Commented by MathematicalUser2357 last updated on 23/Jan/25
$${x}=\frac{−{b}\pm\sqrt{\boldsymbol{{b}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{{ac}}}}{\mathrm{2}{a}} \\ $$
Commented by ajfour last updated on 23/Jan/25
$${a}\left(\frac{−{b}\pm\sqrt{\boldsymbol{{b}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{{ac}}}}{\mathrm{2}{a}}\right)^{\mathrm{2}} +{b}\left(\frac{−{b}\pm\sqrt{\boldsymbol{{b}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{{ac}}}}{\mathrm{2}{a}}\right)+{c}=\mathrm{0} \\ $$