Question Number 216201 by BaliramKumar last updated on 29/Jan/25
Answered by dionigi last updated on 30/Jan/25
$${the}\:{largest}\:{possible}\:{area}\:{is}\: \\ $$$${that}\:{of}\:{an}\:{equilateral}\:{triangle} \\ $$$${with}\:{side}\:\mathrm{60}/\mathrm{3}\:=\:\mathrm{20}\:{cm} \\ $$$${A}\:\leqslant\:\frac{\mathrm{1}}{\mathrm{2}}\:×\:\mathrm{20}\:×\:\mathrm{20}\:×\:\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:=\:\mathrm{173}.\mathrm{205}…<\mathrm{174} \\ $$