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Question Number 216560 by Tawa11 last updated on 10/Feb/25
An object of mass M, initially at rest at the  coordinate origin, explodes into three parts.  Fragment A has a mass M/2, and fragments  B and C have a mass M/4 each.    After the explosion, fragment A moves in  the +X direction at 10 m/s and fragment  B moves in the +Y direction at 8 m/s.  Find the direction and speed of fragment C
An object of mass M, initially at rest at the
coordinate origin, explodes into three parts.
Fragment A has a mass M/2, and fragments
B and C have a mass M/4 each.

After the explosion, fragment A moves in
the +X direction at 10 m/s and fragment
B moves in the +Y direction at 8 m/s.
Find the direction and speed of fragment C

Answered by mr W last updated on 12/Feb/25
m_C u_(Cx) +m_A u_(Ax) =0  ⇒u_(Cx) =−((0.5×10)/(0.25))=−20 m/s  m_C u_(Cy) +m_B u_(By) =0  ⇒u_(Cy) =−((0.25×8)/(0.25))=−8 m/s  ∣u_C ∣=(√((−20)^2 +(−8)^2 ))=21.54 m/s  θ=180°+tan^(−1) (8/(20))=201.8°
$${m}_{{C}} {u}_{{Cx}} +{m}_{{A}} {u}_{{Ax}} =\mathrm{0} \\ $$$$\Rightarrow{u}_{{Cx}} =−\frac{\mathrm{0}.\mathrm{5}×\mathrm{10}}{\mathrm{0}.\mathrm{25}}=−\mathrm{20}\:{m}/{s} \\ $$$${m}_{{C}} {u}_{{Cy}} +{m}_{{B}} {u}_{{By}} =\mathrm{0} \\ $$$$\Rightarrow{u}_{{Cy}} =−\frac{\mathrm{0}.\mathrm{25}×\mathrm{8}}{\mathrm{0}.\mathrm{25}}=−\mathrm{8}\:{m}/{s} \\ $$$$\mid{u}_{{C}} \mid=\sqrt{\left(−\mathrm{20}\right)^{\mathrm{2}} +\left(−\mathrm{8}\right)^{\mathrm{2}} }=\mathrm{21}.\mathrm{54}\:{m}/{s} \\ $$$$\theta=\mathrm{180}°+\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{8}}{\mathrm{20}}=\mathrm{201}.\mathrm{8}° \\ $$
Commented by Tawa11 last updated on 11/Feb/25
Thanks sir.  I appreciate.
$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{appreciate}. \\ $$

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