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Question-216821




Question Number 216821 by BaliramKumar last updated on 22/Feb/25
Answered by AntonCWX08 last updated on 22/Feb/25
AE×BE=25×4=100  AE×BE=100  100  =1×100  =2×50  =4×25  =5×20  =10×10  =20×5  =25×4  =50×2  =100×1    There are 9 values  5 values if consider AE≥BE    min(AB)=20  max(AB)=101
$${AE}×{BE}=\mathrm{25}×\mathrm{4}=\mathrm{100} \\ $$$${AE}×{BE}=\mathrm{100} \\ $$$$\mathrm{100} \\ $$$$=\mathrm{1}×\mathrm{100} \\ $$$$=\mathrm{2}×\mathrm{50} \\ $$$$=\mathrm{4}×\mathrm{25} \\ $$$$=\mathrm{5}×\mathrm{20} \\ $$$$=\mathrm{10}×\mathrm{10} \\ $$$$=\mathrm{20}×\mathrm{5} \\ $$$$=\mathrm{25}×\mathrm{4} \\ $$$$=\mathrm{50}×\mathrm{2} \\ $$$$=\mathrm{100}×\mathrm{1} \\ $$$$ \\ $$$${There}\:{are}\:\mathrm{9}\:{values} \\ $$$$\mathrm{5}\:{values}\:{if}\:{consider}\:{AE}\geqslant{BE} \\ $$$$ \\ $$$${min}\left({AB}\right)=\mathrm{20} \\ $$$${max}\left({AB}\right)=\mathrm{101} \\ $$
Commented by BaliramKumar last updated on 22/Feb/25
if   AE, BE ∈ R
$${if}\:\:\:{AE},\:{BE}\:\in\:{R} \\ $$

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