Question Number 216998 by hardmath last updated on 26/Feb/25
Commented by mr W last updated on 26/Feb/25
$${ceva}'{s}\:{theorem} \\ $$
Commented by hardmath last updated on 26/Feb/25
$$ \\ $$$$ \\ $$The proof of the mentioned is the laxim
Commented by mr W last updated on 26/Feb/25
https://mathmonks.com/cevas-theorem