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Parties-a-b-c-d-For-a-convex-quadrilateral-Prove-that-Area-ABCD-a-2-b-2-c-2-d-2-4-




Question Number 217047 by hardmath last updated on 27/Feb/25
Parties - a,b,c,d  For a convex quadrilateral  Prove that:  Area(ABCD) ≤ ((a^2  + b^2  + c^2  + d^2 )/4)
$$\mathrm{Parties}\:-\:\mathrm{a},\mathrm{b},\mathrm{c},\mathrm{d} \\ $$$$\mathrm{For}\:\mathrm{a}\:\mathrm{convex}\:\mathrm{quadrilateral} \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{Area}\left(\mathrm{ABCD}\right)\:\leqslant\:\frac{\mathrm{a}^{\mathrm{2}} \:+\:\mathrm{b}^{\mathrm{2}} \:+\:\mathrm{c}^{\mathrm{2}} \:+\:\mathrm{d}^{\mathrm{2}} }{\mathrm{4}} \\ $$

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