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Find-32-1-5-3-8-1-8-




Question Number 217197 by hardmath last updated on 05/Mar/25
Find:  ((−32))^(1/5)   +  (((−3)^8 ))^(1/8)   =  ?
$$\mathrm{Find}: \\ $$$$\sqrt[{\mathrm{5}}]{−\mathrm{32}}\:\:+\:\:\sqrt[{\mathrm{8}}]{\left(−\mathrm{3}\right)^{\mathrm{8}} }\:\:=\:\:? \\ $$
Answered by Rasheed.Sindhi last updated on 05/Mar/25
((−32))^(1/5)   +  (((−3)^8 ))^(1/8)    =((−32))^(1/5)   +  (((3)^8 ))^(1/8)    =−2+3=1
$$\sqrt[{\mathrm{5}}]{−\mathrm{32}}\:\:+\:\:\sqrt[{\mathrm{8}}]{\left(−\mathrm{3}\right)^{\mathrm{8}} }\: \\ $$$$=\sqrt[{\mathrm{5}}]{−\mathrm{32}}\:\:+\:\:\sqrt[{\mathrm{8}}]{\left(\mathrm{3}\right)^{\mathrm{8}} }\: \\ $$$$=−\mathrm{2}+\mathrm{3}=\mathrm{1} \\ $$

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