Question Number 218309 by 200392jjlv last updated on 05/Apr/25
$$\underset{−\infty} {\overset{\infty} {\int}}\frac{\mathrm{4}}{\mathrm{16}+{x}^{\mathrm{2}} }{dx} \\ $$$$=\:\underset{−\infty} {\overset{\mathrm{0}} {\int}}\frac{\mathrm{4}}{\mathrm{16}+{x}^{\mathrm{2}} }{dx}+\underset{\infty} {\int}^{\mathrm{0}} \frac{\mathrm{4}}{\mathrm{16}+{x}^{\mathrm{2}} }{dx} \\ $$$$=\: \\ $$$$ \\ $$