Question-218887

Question Number 218887 by Spillover last updated on 17/Apr/25

Answered by mr W last updated on 17/Apr/25

Commented by mr W last updated on 17/Apr/25

8^2 +(2(√2))^2 =72=(6(√2))^2 ⇒α=90° A_(blue) =((2×8 sin (45°+90°))/2)=((8×(√2))/2)=4(√2)

$$\mathrm{8}^{\mathrm{2}} +\left(\mathrm{2}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{72}=\left(\mathrm{6}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} \\ $$$$\Rightarrow\alpha=\mathrm{90}° \\ $$$${A}_{{blue}} =\frac{\mathrm{2}×\mathrm{8}\:\mathrm{sin}\:\left(\mathrm{45}°+\mathrm{90}°\right)}{\mathrm{2}}=\frac{\mathrm{8}×\sqrt{\mathrm{2}}}{\mathrm{2}}=\mathrm{4}\sqrt{\mathrm{2}} \\ $$

Commented by Spillover last updated on 17/Apr/25