Question Number 219255 by Spillover last updated on 21/Apr/25
Answered by A5T last updated on 21/Apr/25
$$\mathrm{WLOG},\:\mathrm{let}\:\mathrm{the}\:\mathrm{side},\mathrm{s},\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{be}\:\mathrm{1} \\ $$$$\Rightarrow\mathrm{b}^{\mathrm{2}} =\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} +\mathrm{1}^{\mathrm{2}} =\frac{\mathrm{5}}{\mathrm{4}} \\ $$$$\mathrm{a}×\mathrm{b}=\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{1}}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{4}}\overset{/\mathrm{b}^{\mathrm{2}} } {\Rightarrow}\frac{\mathrm{a}}{\mathrm{b}}=\frac{\mathrm{1}}{\mathrm{4b}^{\mathrm{2}} }=\frac{\mathrm{1}}{\mathrm{5}} \\ $$
Answered by Spillover last updated on 21/Apr/25
Answered by Spillover last updated on 21/Apr/25
Answered by Spillover last updated on 21/Apr/25
Answered by Spillover last updated on 21/Apr/25
Answered by Spillover last updated on 21/Apr/25
