Question Number 219403 by ea last updated on 23/Apr/25
Answered by mr W last updated on 24/Apr/25
Commented by mr W last updated on 24/Apr/25
$$\mathrm{4}{x}^{\mathrm{2}} =\mathrm{2}{b}^{\mathrm{2}} +\mathrm{2}{y}^{\mathrm{2}} −\mathrm{4}{d}^{\mathrm{2}} \\ $$$$\mathrm{4}{y}^{\mathrm{2}} =\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{c}^{\mathrm{2}} −\mathrm{4}{d}^{\mathrm{2}} \\ $$$$\Sigma: \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\mathrm{4}{d}^{\mathrm{2}} ={b}^{\mathrm{2}} +{c}^{\mathrm{2}} \\ $$$$\mid{AX}\mid^{\mathrm{2}} +\mid{AY}\mid^{\mathrm{2}} +\mathrm{4}\mid{XY}\mid^{\mathrm{2}} =\mid{AB}\mid^{\mathrm{2}} +\mid{AC}\mid^{\mathrm{2}} \\ $$
Commented by ea last updated on 24/Apr/25
Perfect sir!