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1-3-1-3-1-3-1-3-1-3-x-1-x-2-x-3-x-4-x-5-x-1-x-2-x-3-x-4-x-5-dx-1-dx-2-dx-3-dx-4-dx-5-




Question Number 219456 by Nicholas666 last updated on 25/Apr/25
   ∫_1 ^( 3) ∫_1 ^( 3) ∫_1 ^( 3) ∫_1 ^( 3) ∫_1 ^( 3)  ((x_1 +x_2 +x_3 +x_4 −x_5 )/(x_1 +x_2 +x_3 +x_4 +x_5 )) dx_1 dx_2 dx_3 dx_4 dx_5
$$ \\ $$$$\:\int_{\mathrm{1}} ^{\:\mathrm{3}} \int_{\mathrm{1}} ^{\:\mathrm{3}} \int_{\mathrm{1}} ^{\:\mathrm{3}} \int_{\mathrm{1}} ^{\:\mathrm{3}} \int_{\mathrm{1}} ^{\:\mathrm{3}} \:\frac{{x}_{\mathrm{1}} +{x}_{\mathrm{2}} +{x}_{\mathrm{3}} +{x}_{\mathrm{4}} −{x}_{\mathrm{5}} }{{x}_{\mathrm{1}} +{x}_{\mathrm{2}} +{x}_{\mathrm{3}} +{x}_{\mathrm{4}} +{x}_{\mathrm{5}} }\:{dx}_{\mathrm{1}} {dx}_{\mathrm{2}} {dx}_{\mathrm{3}} {dx}_{\mathrm{4}} {dx}_{\mathrm{5}} \:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$
Commented by mr W last updated on 26/Apr/25
=(1−(2/5))(3−1)^5 =((96)/5)
$$=\left(\mathrm{1}−\frac{\mathrm{2}}{\mathrm{5}}\right)\left(\mathrm{3}−\mathrm{1}\right)^{\mathrm{5}} =\frac{\mathrm{96}}{\mathrm{5}} \\ $$
Commented by Nicholas666 last updated on 26/Apr/25
thanks
$${thanks} \\ $$

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