Question Number 219998 by fantastic last updated on 04/May/25
Answered by mehdee7396 last updated on 04/May/25
$${AB}=\sqrt{\mathrm{61}}\:\:\&\:\:\:{AC}=\mathrm{6}\sqrt{\mathrm{10}} \\ $$$${S}_{{ABC}} =\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{13}×\mathrm{6}=\mathrm{39} \\ $$$${R}=\frac{{abc}}{\mathrm{4}{S}}=\frac{\mathrm{13}×\sqrt{\mathrm{61}}×\mathrm{6}\sqrt{\mathrm{10}}}{\mathrm{4}×\mathrm{39}}=\frac{\sqrt{\mathrm{610}}}{\mathrm{2}} \\ $$$$ \\ $$
Commented by mehdee7396 last updated on 04/May/25
