Question Number 220493 by leromain last updated on 13/May/25
$${Let}\:{ABC}\:{be}\:{a}\:{triangle}\:{such} \\ $$$${CosA}+{cosB}+{cosC}=\sqrt{\mathrm{2}} \\ $$$${SinA}+{sinB}+{sinC}=\mathrm{1}+\sqrt{\mathrm{2}} \\ $$$${Find}\:{A},{B},{C} \\ $$
Commented by mr W last updated on 13/May/25
$$\mathrm{45}°,\:\mathrm{45}°,\:\mathrm{90}° \\ $$