Question Number 220526 by Larry last updated on 14/May/25
Answered by Frix last updated on 14/May/25
$$=\int{x}^{−\frac{\mathrm{2}}{\mathrm{7}}} {dx}=\frac{\mathrm{7}}{\mathrm{8}}{x}^{\frac{\mathrm{5}}{\mathrm{7}}} +{C} \\ $$
Answered by SdC355 last updated on 14/May/25
$$\int\:\:{z}^{−\frac{\mathrm{2}}{\mathrm{7}}} \mathrm{d}{z}=\frac{\mathrm{1}}{\mathrm{1}−\frac{\mathrm{2}}{\mathrm{7}}}\:{z}^{\mathrm{1}−\frac{\mathrm{2}}{\mathrm{7}}} =\frac{\mathrm{7}}{\mathrm{5}}\:{z}^{\frac{\mathrm{5}}{\mathrm{7}}} +\mathrm{const}. \\ $$