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Question-220831




Question Number 220831 by Nicholas666 last updated on 20/May/25
Answered by mr W last updated on 20/May/25
Commented by mr W last updated on 20/May/25
Area (B+E)=shaded area        =((π×1^2 )/4)−(1^2 /4)=((π−1)/4)  Area (A+C+D+F)=1^2 −Area (B+E)       =1−((π−1)/4)=((5−π)/4)  ((Area (A+C+D+F) )/(Area (B+E)))=((5−π)/(π−1))≈0.868
$${Area}\:\left({B}+{E}\right)={shaded}\:{area}\: \\ $$$$\:\:\:\:\:=\frac{\pi×\mathrm{1}^{\mathrm{2}} }{\mathrm{4}}−\frac{\mathrm{1}^{\mathrm{2}} }{\mathrm{4}}=\frac{\pi−\mathrm{1}}{\mathrm{4}} \\ $$$${Area}\:\left({A}+{C}+{D}+{F}\right)=\mathrm{1}^{\mathrm{2}} −{Area}\:\left({B}+{E}\right) \\ $$$$\:\:\:\:\:=\mathrm{1}−\frac{\pi−\mathrm{1}}{\mathrm{4}}=\frac{\mathrm{5}−\pi}{\mathrm{4}} \\ $$$$\frac{{Area}\:\left({A}+{C}+{D}+{F}\right)\:}{{Area}\:\left({B}+{E}\right)}=\frac{\mathrm{5}−\pi}{\pi−\mathrm{1}}\approx\mathrm{0}.\mathrm{868} \\ $$

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