Question Number 221707 by Tawa11 last updated on 09/Jun/25

Commented by Tawa11 last updated on 09/Jun/25

In the ∆ABC |AB|=|BC|=|AC|=K, Area of
the shaded ∆ is (225/K )cm².
Find the height of the triangle ∆ABC.
the shaded ∆ is (225/K )cm².
Find the height of the triangle ∆ABC.
Commented by fantastic last updated on 09/Jun/25

$${please}\:{clarify}\:{the}\:{drawing}\:{and}\:{the}\:{statement} \\ $$
Commented by Tawa11 last updated on 09/Jun/25

Commented by Tawa11 last updated on 09/Jun/25

$$\mathrm{This}\:\mathrm{is}\:\mathrm{what}\:\mathrm{they}\:\mathrm{drew}\:\mathrm{again}. \\ $$
Commented by Tawa11 last updated on 09/Jun/25
The height of triangle can be found
using Viviani's theorem.
They mention this too.
Commented by fantastic last updated on 09/Jun/25

$${is}\:{there}\:{anything}\:{given}\:{about}\:{the}\:{size}\:{of}\:{the}\:{circles}? \\ $$
Commented by Tawa11 last updated on 09/Jun/25
OM is perpendicular to AC
And ON is perpendicular to BC
Commented by fantastic last updated on 09/Jun/25

$${i}\:{will}\:{try} \\ $$
Commented by Tawa11 last updated on 09/Jun/25

$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$
Commented by fantastic last updated on 09/Jun/25

$${the}\:{question}\:{itself}\:{is}\:{wrong}\:.{just}\:{think}\: \\ $$$${the}\:{virtically}\:{opposite}\:{angle}\:{of}\:\measuredangle{NO}\:..\:{is}\:\mathrm{90}^{\mathrm{0}\:} \\ $$$${how}\:{is}\:{that}\:{possible}?? \\ $$
Commented by Tawa11 last updated on 09/Jun/25

Commented by Tawa11 last updated on 09/Jun/25

Commented by Tawa11 last updated on 09/Jun/25

$$\mathrm{Is}\:\mathrm{this}\:\mathrm{correct}? \\ $$
Answered by fantastic last updated on 09/Jun/25
