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1-x-4-y-x-3-y-x-5-x-3-2x-1-

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Question Number 222296 by Shrodinger last updated on 22/Jun/25
(1+x^4 )y′−x^3 y = x^5 −x^3 +2x+1
$$\left(\mathrm{1}+{x}^{\mathrm{4}} \right){y}'−{x}^{\mathrm{3}} {y}\:=\:{x}^{\mathrm{5}} −{x}^{\mathrm{3}} +\mathrm{2}{x}+\mathrm{1} \\ $$

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