Question Number 222334 by SonGoku last updated on 22/Jun/25
Commented by SonGoku last updated on 22/Jun/25
$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{Rectangle}? \\ $$
Commented by mr W last updated on 22/Jun/25
$${area}\:{of}\:{rectangle}\: \\ $$$$\:\:=\mathrm{2}×\:{area}\:{of}\:{triangle} \\ $$$$\:\:=\frac{\sqrt{\left({a}+{b}+{c}\right)\left(−{a}+{b}+{c}\right)\left({a}−{b}+{c}\right)\left({a}+{b}−{c}\right)}}{\mathrm{2}} \\ $$
Commented by SonGoku last updated on 22/Jun/25
$$\mathrm{Thanks}! \\ $$
Commented by mr W last updated on 25/Jun/25
$${or} \\ $$$$\mathrm{69}.\mathrm{03}×\mathrm{115}.\mathrm{05}×\sqrt{\mathrm{1}−\left(\frac{\mathrm{69}.\mathrm{03}^{\mathrm{2}} +\mathrm{115}.\mathrm{05}^{\mathrm{2}} −\mathrm{161}.\mathrm{07}^{\mathrm{2}} }{\mathrm{2}×\mathrm{69}.\mathrm{03}×\mathrm{115}.\mathrm{05}}\right)^{\mathrm{2}} } \\ $$$$\approx\mathrm{6877}.\mathrm{888} \\ $$
Answered by MathematicalUser2357 last updated on 25/Jun/25
$$\frac{\mathrm{69}.\mathrm{03}+\mathrm{115}.\mathrm{05}+\mathrm{161}.\mathrm{07}}{\mathrm{2}} \\ $$$$\mathrm{172}.\mathrm{575} \\ $$$$\sqrt{\mathrm{172}.\mathrm{575}×\left(\mathrm{172}.\mathrm{575}−\mathrm{69}.\mathrm{03}\right)×\left(\mathrm{172}.\mathrm{575}−\mathrm{115}.\mathrm{05}\right)×\left(\mathrm{172}.\mathrm{575}−\mathrm{161}.\mathrm{07}\right)} \\ $$$$\mathrm{3438}.\mathrm{944227} \\ $$